Based on the following electrochemical data, which is the strongest oxidizing agen Hg2+(aq) + 2e → Hg(1) E°red = +0.85 V Cr20-2(aq) + 14H*(aq) + 6e¯ 2Cr³+(aq) + 7H20(1) E°red = +1.33 V Ca2+(aq) + 2e¯ –→ Ca(s) E°red = -2.76 V Zn2+(aq) + 2e¯ → Zn(s) E°red = -0.76 V NO3 (aq) + 4H+(aq) + 3e¯ → NO(g) + 2H2O(1) E°red = +0.96 V %3D
Based on the following electrochemical data, which is the strongest oxidizing agen Hg2+(aq) + 2e → Hg(1) E°red = +0.85 V Cr20-2(aq) + 14H*(aq) + 6e¯ 2Cr³+(aq) + 7H20(1) E°red = +1.33 V Ca2+(aq) + 2e¯ –→ Ca(s) E°red = -2.76 V Zn2+(aq) + 2e¯ → Zn(s) E°red = -0.76 V NO3 (aq) + 4H+(aq) + 3e¯ → NO(g) + 2H2O(1) E°red = +0.96 V %3D
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Based on the following electrochemical data, which is the strongest oxidizing agen
Hg2+(aq) + 2e →
Hg(1)
E°red
= +0.85 V
Cr20-2(aq) + 14H*(aq) + 6e¯
2Cr³+(aq) + 7H20(1)
E°red = +1.33 V
Ca2+(aq) + 2e¯ –→ Ca(s)
E°red = -2.76 V
Zn2+(aq) + 2e¯ → Zn(s)
E°red = -0.76 V
NO3 (aq) + 4H+(aq) + 3e¯ → NO(g) + 2H2O(1)
E°red = +0.96 V
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F85d2b800-ee72-401d-a12b-d9e7bf0f8171%2F774a82db-7fbe-480f-8fe3-3eda3308019e%2F9tevbpc.jpeg&w=3840&q=75)
Transcribed Image Text:Based on the following electrochemical data, which is the strongest oxidizing agen
Hg2+(aq) + 2e →
Hg(1)
E°red
= +0.85 V
Cr20-2(aq) + 14H*(aq) + 6e¯
2Cr³+(aq) + 7H20(1)
E°red = +1.33 V
Ca2+(aq) + 2e¯ –→ Ca(s)
E°red = -2.76 V
Zn2+(aq) + 2e¯ → Zn(s)
E°red = -0.76 V
NO3 (aq) + 4H+(aq) + 3e¯ → NO(g) + 2H2O(1)
E°red = +0.96 V
%3D
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Step 1
Oxidizing agent : If the reduction potential of a species is high or more positive then it will acts as an oxidising agent i.e. it will oxidised another species but reduced itself.
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