Calculate the potential, Ereduction, for the given half-reaction at pH = 7 and 1 M concentrations of all other aqueous species. RuO4 (aq) + 6 H3O* (aq) + 4 e¯ – Ru(OH)22* (aq) + 8 H2O (I) E°reduction = +1.40 V - 1.08 V O+1.40 V + 0.88 V + 0.78 V + 1.30 V
Calculate the potential, Ereduction, for the given half-reaction at pH = 7 and 1 M concentrations of all other aqueous species. RuO4 (aq) + 6 H3O* (aq) + 4 e¯ – Ru(OH)22* (aq) + 8 H2O (I) E°reduction = +1.40 V - 1.08 V O+1.40 V + 0.88 V + 0.78 V + 1.30 V
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![Calculate the potential, Ereduction, for the given half-reaction at pH = 7 and 1 M
concentrations of all other aqueous species.
RuO4 (aq) + 6 H30* (aq) + 4 e¯ → Ru(OH)22* (aq) + 8 H2O (1) E°reduction = +1.40 V
%3D
O- 1.08 V
+ 1.40 V
+ 0.88 V
+ 0.78 V
+ 1.30 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1ba6bbb-fc76-4ff1-897e-f936bd2be4a6%2Fb51f3ce8-7c74-4426-8ee9-696153033e32%2Fdv9s2k7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculate the potential, Ereduction, for the given half-reaction at pH = 7 and 1 M
concentrations of all other aqueous species.
RuO4 (aq) + 6 H30* (aq) + 4 e¯ → Ru(OH)22* (aq) + 8 H2O (1) E°reduction = +1.40 V
%3D
O- 1.08 V
+ 1.40 V
+ 0.88 V
+ 0.78 V
+ 1.30 V
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