Separation d (_10_ m) Plate Area A (. 100 m:) Capacitance C.= (ɛ,*A)/d_(_9.0x10^14_F) Trial Potential Charge Stored Electric Field v2 Q? E2 Stored energy difference Q (C) V (V) (V/m)2 | Density uJ/m³) u=U/(Ad) Energy between (Volt)? (c2) U () plates E (V/m) U= 1/2•E0•E4 1 -1.5 1.3x10- 1.0x10- -.15 -2.25 1.69x1 -.0225 -9.9x10-14 13 13 0-26 -1.3 1.2x10- 7.0x10- -.13 -1.69 1.44x1 -.0169 -7.5x10-14 13 14 0-26 3 -1.0 9.0x10- 4.0x10- -.10 -1.0 8.1x10 -.001 -4.4x10-15 14 14 -27 4 -0.7 6.0x10- 2.0x10- -.07 -0.49 3.6x10 -.0049 -2.2x10-14 14 14 -27 5 -0.4 4.0x10- 1.0x10- -.04 -0.16 1.6x10 -.0016 -7.08x10-15 14 14 -27 6 .04 4.0x10- 1.0x10- .04 0.16 1.6x10 .0016 7.08x10-15 14 14 -27 7 .07 6.0x10- 2.0x10- .07 0.49 3.6x10 .0049 2.2x10-14 14 14 -27 1.0 9.0x10- 4.0x10- .10 1.0 8.1.0x .001 4.4x10-15 14 14 10-27 9 1.3 1.2x10- 7.0x10- .13 1.69 1.44x1 .0169 7.5x10-14 13 14 0-26 10 1.5 1.3x10- 1.0x10- .15 2.25 1.69x1 .0225 9.9x10-14 13 13 0-26 00
Separation d (_10_ m) Plate Area A (. 100 m:) Capacitance C.= (ɛ,*A)/d_(_9.0x10^14_F) Trial Potential Charge Stored Electric Field v2 Q? E2 Stored energy difference Q (C) V (V) (V/m)2 | Density uJ/m³) u=U/(Ad) Energy between (Volt)? (c2) U () plates E (V/m) U= 1/2•E0•E4 1 -1.5 1.3x10- 1.0x10- -.15 -2.25 1.69x1 -.0225 -9.9x10-14 13 13 0-26 -1.3 1.2x10- 7.0x10- -.13 -1.69 1.44x1 -.0169 -7.5x10-14 13 14 0-26 3 -1.0 9.0x10- 4.0x10- -.10 -1.0 8.1x10 -.001 -4.4x10-15 14 14 -27 4 -0.7 6.0x10- 2.0x10- -.07 -0.49 3.6x10 -.0049 -2.2x10-14 14 14 -27 5 -0.4 4.0x10- 1.0x10- -.04 -0.16 1.6x10 -.0016 -7.08x10-15 14 14 -27 6 .04 4.0x10- 1.0x10- .04 0.16 1.6x10 .0016 7.08x10-15 14 14 -27 7 .07 6.0x10- 2.0x10- .07 0.49 3.6x10 .0049 2.2x10-14 14 14 -27 1.0 9.0x10- 4.0x10- .10 1.0 8.1.0x .001 4.4x10-15 14 14 10-27 9 1.3 1.2x10- 7.0x10- .13 1.69 1.44x1 .0169 7.5x10-14 13 14 0-26 10 1.5 1.3x10- 1.0x10- .15 2.25 1.69x1 .0225 9.9x10-14 13 13 0-26 00
College Physics
11th Edition
ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Slope: 4.414x10-14
Use the equation U = 1/2 CV2 , to determine C0 using the slope, and compare this value of C0 with C0 above the table, then calculate the percentage error.
Transcribed Image Text:Separation d (_10__ m) Plate Area A (_
_100
m?) Capacitance C,=(ɛ,*A)/d__9.0x10^14_F)
Trial
Potential
Charge
Stored
Electric Field
v2
Q?
E?
Stored energy
difference Q (C)
V (V)
Energy
between
U ()
(Volt)? | (C?)
(V/m)² |
Density u(J/m3)
u=U/(Ad)
plates E (V/m)
U= 1/2•€0•E4
*
1
-1.5
1.3x10-
1.0x10-
-.15
-2.25
1.69x1
-.0225
-9.9x10-14
13
13
0-26
2
-1.3
1.2x10-
7.0x10-
-.13
-1.69
1.44x1
-.0169
-7.5x10-14
13
14
0-26
3
-1.0
9.0x10-
4.0x10-
-.10
-1.0
8.1x10
-.001
-4.4x10-15
14
14
-27
4
-0.7
6.0x10-
2.0х10-
-.07
-0.49
3.6х10
-.0049
-2.2x10-14
14
14
-27
-0.4
4.0x10-
1.0x10-
-.04
-0.16
1.6x10| -.0016
-7.08x10-15
14
14
-27
.04
4.0x10-
1.0x10-
.04
0.16
1.6x10
.0016
7.08х10-15
14
14
-27
.07
6.0x10-
2.0x10-
.07
0.49
3.6х10
.0049
2.2x10-14
14
14
-27
8
1.0
9.0x10-
4.0x10-
.10
1.0
8.1.0x
.001
4.4x10-15
14
14
10-27
1.3
1.2x10-
7.0x10-
.13
1.69
1.44x1
.0169
7.5x10-14
13
14
0-26
10
1.5
1.3x10-
1.0x10-
.15
2.25
1.69x1
.0225
9.9x10-14
13
13
0-26
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