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measuring the changes in volume and surface area of worms. Two worms labeled A and B st the beginning of the study having the same initial volume and the same surface area. At the the study, both worms grew isometrically, but the relative surface area RSA of worm A is gre than that of worm B by a factor of 1.3. Take relative surface area to mean the ratio of surfac volume. Which of the two worms has the larger volume at the end of the study? Both worms have the same volume O Worm A Information provided is not enough to answer O Worm B

measuring the changes in volume and surface area of worms. Two worms labeled A and B st the beginning of the study having the same initial volume and the same surface area. At the the study, both worms grew isometrically, but the relative surface area RSA of worm A is gre than that of worm B by a factor of 1.3. Take relative surface area to mean the ratio of surfac volume. Which of the two worms has the larger volume at the end of the study? Both worms have the same volume O Worm A Information provided is not enough to answer O Worm B

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question 18, Physics - equation sheet attached

Physics 114 Equation Sheet Constants and Conversions Kinematics Continued g = 9.80 m/s Free-fall acceleration Δν Instantaneous ainst. = lim At-o At Acceleration 1N = 1 kg m/s? Newton Uniform motion (v) = (v); = constant Position in uniform X = x + (v)At Mathematics, Scaling and Vectors b = a* + loga (b) = x motion Logarithm Constant (v); = (v,); + azAt acceleration: 1 log(ab) = log(a) + log (b) x, = x, + (v,),At +a, (at)? log Ax" = n log x + log A (v,); = (v,)} + 2a,Ax Volume of a sphere V = Surface area of a A = 4ar? Forces sphere Newton's second law Fnet = EF = mã %3D Volume of a cylinder V = arl Newton's second law Fnetx = EF = ma, %3D Surface area of a A = 2ar? + 2rl Component form Fnety = ER, = may cylinder Mass density p = m/V Newton's Third Law FA en =- ton A A, = A cos e (rel. to x-axis) Weight w = mg x -component of a vector Å Apparent weight Wapp = magnitude of supporting forces y -component of a Ay = A sin 8 (rel to x-axis) vector Å Kinetic friction fk = Han Magnitude of vector Ả Static friction A = JA + A, Reynolds number Re = pvl/n Direction of A relative 8 = tan-(Ay/A,) 1 Drag (high Reynolds number) =CopAv? to x-axis Addition of two vectors If = Å + B, then C, = A, + B, D = 6nyrv Drag (low Reynolds number) Cy = Ay + By Circular Motion Kinematics Centripetal acceleration a = Displacement Ax = x - X Average Velocity Ax Frequency 1 Varg T 2ar At Ax Vinst. = lim Instantaneous Velocity At+0 At Av Average Acceleration davg Δε
Transcribed Image Text:Physics 114 Equation Sheet Constants and Conversions Kinematics Continued g = 9.80 m/s Free-fall acceleration Δν Instantaneous ainst. = lim At-o At Acceleration 1N = 1 kg m/s? Newton Uniform motion (v) = (v); = constant Position in uniform X = x + (v)At Mathematics, Scaling and Vectors b = a* + loga (b) = x motion Logarithm Constant (v); = (v,); + azAt acceleration: 1 log(ab) = log(a) + log (b) x, = x, + (v,),At +a, (at)? log Ax" = n log x + log A (v,); = (v,)} + 2a,Ax Volume of a sphere V = Surface area of a A = 4ar? Forces sphere Newton's second law Fnet = EF = mã %3D Volume of a cylinder V = arl Newton's second law Fnetx = EF = ma, %3D Surface area of a A = 2ar? + 2rl Component form Fnety = ER, = may cylinder Mass density p = m/V Newton's Third Law FA en =- ton A A, = A cos e (rel. to x-axis) Weight w = mg x -component of a vector Å Apparent weight Wapp = magnitude of supporting forces y -component of a Ay = A sin 8 (rel to x-axis) vector Å Kinetic friction fk = Han Magnitude of vector Ả Static friction A = JA + A, Reynolds number Re = pvl/n Direction of A relative 8 = tan-(Ay/A,) 1 Drag (high Reynolds number) =CopAv? to x-axis Addition of two vectors If = Å + B, then C, = A, + B, D = 6nyrv Drag (low Reynolds number) Cy = Ay + By Circular Motion Kinematics Centripetal acceleration a = Displacement Ax = x - X Average Velocity Ax Frequency 1 Varg T 2ar At Ax Vinst. = lim Instantaneous Velocity At+0 At Av Average Acceleration davg Δε
A researcher is studying the absorption and consumption of oxygen through the skin of worms by measuring the changes in volume and surface area of worms. Two worms labeled A and B start off at the beginning of the study having the same initial volume and the same surface area. At the end of the study, both worms grew isometrically, but the relative surface area RSA of worm A is greater than that of worm B by a factor of 1.3. Take relative surface area to mean the ratio of surface area to volume. Which of the two worms has the larger volume at the end of the study? O Both worms have the same volume O Worm A O Information provided is not enough to answer O Worm B
Transcribed Image Text:A researcher is studying the absorption and consumption of oxygen through the skin of worms by measuring the changes in volume and surface area of worms. Two worms labeled A and B start off at the beginning of the study having the same initial volume and the same surface area. At the end of the study, both worms grew isometrically, but the relative surface area RSA of worm A is greater than that of worm B by a factor of 1.3. Take relative surface area to mean the ratio of surface area to volume. Which of the two worms has the larger volume at the end of the study? O Both worms have the same volume O Worm A O Information provided is not enough to answer O Worm B
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