Q13) A 7.5 x 10'N upward tension force is exerted on a 521 kg downward moving elevator. The acceleration in m/s² of the elevator is: (g-9.8 m/s²) a. -3.36 b. -2.83 c. -4.5 d. -9.80
Q13) A 7.5 x 10'N upward tension force is exerted on a 521 kg downward moving elevator. The acceleration in m/s² of the elevator is: (g-9.8 m/s²) a. -3.36 b. -2.83 c. -4.5 d. -9.80
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ISBN:9781305952300
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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physics, pleaassssse solve question 13

Transcribed Image Text:Q8) A particle confined to motion along the x axis moves with constant acceleration
from x 2.0 m to x 8.0 m during a 2.5-s time interval. The velocity of the
particle at x 8.0 m is 2.8 m/s. What is the acceleration during this time interval?
a. -0.2 m/s²
b. 0.32 m/s²
#WA motion of a particle is defined by x(t)=5+3+1+21, where x is in meter and t is in seconds,
answer (Q9,Q10).
Q9) The average acceleration of the particle (in m/s) between t-0 and 1-2 (s) is
a. 6
b. 14
Q10) The acceleration of particle at 1-2 sec. in m/s²:
a.38
b. 26
a. g(mm₂)/(m₁+m₂)
c. g (m₂m₁)/(m+m₂)
A) 5.3
c.0.64 m/s²
a. -3.36
B) 4.4
c. 8
c. 10
Q11.Two masses, m, and my, are hanging by a massless string from a frictionless pulley. If m, is
greater than my, determine the acceleration of the two masses when released from rest.
b. g (m+m₂)/(m₁-m₂)
d. g (m₂.m₁)/(my-m₁)
b. -2.83
Q12) If F 5.0 N and m-2.0 kg, what is the magnitude a of the acceleration in m/s for the
block shown below? The surface is frictionless
d.0.80 m/s²
d. 2
C)3.5
d. 2
c. -4.5
Q13) A 7.5 x 10' N upward tension force is exerted on a 521 kg downward moving elevator.
The acceleration in m/s² of the elevator is: (g-9.8 m/s²)
D) 2 E) 6.2
m.
d. -9.80
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