A sailing boat moves on water at constant acceleration to the right. The boat is pushed by the wind with a horizontal force. In the presence of friction with the water and air drag (air resistance), choose che free-body diagram that could represent the forces on the boat.
A sailing boat moves on water at constant acceleration to the right. The boat is pushed by the wind with a horizontal force. In the presence of friction with the water and air drag (air resistance), choose che free-body diagram that could represent the forces on the boat.
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ISBN:9781305952300
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question 17, Physics - equation sheet attached
![A sailing boat moves on water at constant acceleration to the right. The boat is pushed by the wind
with a horizontal force. In the presence of friction with the water and air drag (air resistance), choose
the free-body diagram that could represent the forces on the boat.
+t](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fea74ad9f-1200-44ca-9ede-5ca983ad5349%2F56ba8b73-454e-4f0c-8a68-cfcde0f19849%2F2czr4md_processed.png&w=3840&q=75)
Transcribed Image Text:A sailing boat moves on water at constant acceleration to the right. The boat is pushed by the wind
with a horizontal force. In the presence of friction with the water and air drag (air resistance), choose
the free-body diagram that could represent the forces on the boat.
+t
![Physics 114 Equation Sheet
Constants and Conversions
Kinematics Continued
g = 9.80 m/s
Free-fall acceleration
Δν
Instantaneous
ainst. = lim
At-o At
Acceleration
1N = 1 kg m/s?
Newton
Uniform motion
(v) = (v); = constant
Position in uniform
X = x + (v)At
Mathematics, Scaling and Vectors
b = a* + loga (b) = x
motion
Logarithm
Constant
(v); = (v,); + azAt
acceleration:
1
log(ab) = log(a) + log (b)
x, = x, + (v,),At +a, (at)?
log Ax" = n log x + log A
(v,); = (v,)} + 2a,Ax
Volume of a sphere
V =
Surface area of a
A = 4ar?
Forces
sphere
Newton's second law
Fnet = EF = mã
%3D
Volume of a cylinder
V = arl
Newton's second law
Fnetx = EF = ma,
%3D
Surface area of a
A = 2ar? + 2rl
Component form
Fnety = ER, = may
cylinder
Mass density
p = m/V
Newton's Third Law
FA en =-
ton A
A, = A cos e (rel. to x-axis)
Weight
w = mg
x -component of a
vector Å
Apparent weight
Wapp = magnitude of supporting forces
y -component of a
Ay = A sin 8 (rel to x-axis)
vector Å
Kinetic friction
fk = Han
Magnitude of vector Ả
Static friction
A = JA + A,
Reynolds number
Re = pvl/n
Direction of A relative
8 = tan-(Ay/A,)
1
Drag (high Reynolds
number)
=CopAv?
to x-axis
Addition of two vectors If = Å + B, then
C, = A, + B,
D = 6nyrv
Drag (low Reynolds
number)
Cy = Ay + By
Circular Motion
Kinematics
Centripetal acceleration
a =
Displacement
Ax = x - X
Average Velocity
Ax
Frequency
1
Varg
T
2ar
At
Ax
Vinst. = lim
Instantaneous Velocity
At+0 At
Av
Average Acceleration
davg
Δε](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fea74ad9f-1200-44ca-9ede-5ca983ad5349%2F56ba8b73-454e-4f0c-8a68-cfcde0f19849%2F8l8n8w_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Physics 114 Equation Sheet
Constants and Conversions
Kinematics Continued
g = 9.80 m/s
Free-fall acceleration
Δν
Instantaneous
ainst. = lim
At-o At
Acceleration
1N = 1 kg m/s?
Newton
Uniform motion
(v) = (v); = constant
Position in uniform
X = x + (v)At
Mathematics, Scaling and Vectors
b = a* + loga (b) = x
motion
Logarithm
Constant
(v); = (v,); + azAt
acceleration:
1
log(ab) = log(a) + log (b)
x, = x, + (v,),At +a, (at)?
log Ax" = n log x + log A
(v,); = (v,)} + 2a,Ax
Volume of a sphere
V =
Surface area of a
A = 4ar?
Forces
sphere
Newton's second law
Fnet = EF = mã
%3D
Volume of a cylinder
V = arl
Newton's second law
Fnetx = EF = ma,
%3D
Surface area of a
A = 2ar? + 2rl
Component form
Fnety = ER, = may
cylinder
Mass density
p = m/V
Newton's Third Law
FA en =-
ton A
A, = A cos e (rel. to x-axis)
Weight
w = mg
x -component of a
vector Å
Apparent weight
Wapp = magnitude of supporting forces
y -component of a
Ay = A sin 8 (rel to x-axis)
vector Å
Kinetic friction
fk = Han
Magnitude of vector Ả
Static friction
A = JA + A,
Reynolds number
Re = pvl/n
Direction of A relative
8 = tan-(Ay/A,)
1
Drag (high Reynolds
number)
=CopAv?
to x-axis
Addition of two vectors If = Å + B, then
C, = A, + B,
D = 6nyrv
Drag (low Reynolds
number)
Cy = Ay + By
Circular Motion
Kinematics
Centripetal acceleration
a =
Displacement
Ax = x - X
Average Velocity
Ax
Frequency
1
Varg
T
2ar
At
Ax
Vinst. = lim
Instantaneous Velocity
At+0 At
Av
Average Acceleration
davg
Δε
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