Sand cone equipment is used to perform a field density test on a compacted earth fill.• Sil sample dug from the test hole = 20.60 N• Dry weight of soil sample = 17.92 NOttawa sand used to fill the hole weighs 16.05 N and is known to have a density of 15.74 kN/m³.Which of the following gives the water content of the tested soil?O a.15.45%O b. 12.08%O . 11.12%d. 14.96%e. 10.94%Clear my choice

Given data in question Weight of soil sample dug out Weight of dried soil sample dug out Weight of…

Answered: Sand cone equipment is used to perform…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Results from liquid and plastic limit tests conducted on a soil are given below. Liquid limit tests: Number of blows, N Moisture content (%) 14 38.4 16 36.5 20 33.1 28 27.0 Plastic limit tests: PL = 13.4% a. Draw the flow curve and obtain the liquid limit. b. What is the plasticity index of the soil? © Cengage Learning 2014
a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After adding some water, the degree of saturation was altered to 53%. take the specific gravity of the soil solids to be 2.7. assuming no change in the volume of the voids, determine the following A. void ratio B. water content% C. bulk specific gravity of the mass of the sample in the altered state.
Geotechnical Engineering Please help me answer this question, and please show your solutions write it properly. Problem 3 A soil sample with a grain specific gravity of 2.67 was filled in a 1000mL container in the loosest possible state and the dry unit weight of the sample was found to be 14.75 N. It was then filled at the densest obtainable state and the weight was found to be 17.70 N. The void ratio of the soil in the natural state was 0.63. Determine the relative density in the natural state.
A sample of saturated clay was placed in a container and weighed. The weight was 6N. The clay in its container was placed in an oven for 24 hours at 105˚C. The weight reduced to a constant value of 5N. The weight of the container is 1N. If Gs = 2.7, determine: a) Water Content b) Void Ratio c) Bulk Unit Weight d) Dry Unit Weight e) Effective Unit Weight
A field sand cone test is performed on a layer of compacted fill. determined that the fill soil has a maximum dry unit weight of approximately 120 pcf. Determine the relative compaction of the compacted fill. Unit weight of dry uniform of sand: 95 pcf Weight of sand to fill the cone: 1.10 lb weight of jar + cone + sand (before test): 16.5 lb Weight of jar + cone + sand (after test): 10.5 lb Weight of moist soil excavated from hole: 6.60 lb Moisture content of soil from hole: 10 %
Problem: For a constant laboratory permeability test on a fine sand, the following data are given: Length of specimen - 16 cm Diameter of specimen - 9.6 cm Constant head difference - 50 cm Volume of water collected in 4 min - 420 cc Void ratio of the soil specimen - 0.55 A.) Determine the hydraulic conductivity of the soil in cm/sec B.) Determine the discharge velocity in cm/sec C.) Determine seepage velocity in cm/sec
Following are the results of a field unit-weight determination test performed on the same soil by means of the sand cone method: -Calibrated dry unit weight of Ottawa sand = 15.4019 kn/m3 -Calibrated weight of Ottawa sand to fill the cone = 5.3496 N -Weightof jar + cone + sand (before use) = 74.451 N -Weightof jar + cone + sand (after use) = 46.886 N -Weight of moist soil from hole = 29.509 N -Moisture content of moist soil = 10.21% DETERMINE AND SHOW COMPLETE SOLUTION 1. Dry density of compaction in the field in kg/cu.m.
An undisturbed sample of fine sand is tested in the laboratory and found to have a dry mass of 4.63 kg, a total volume of 0.00198 m³ and a specific gravity of 2.70. Other laboratory tests are performed to determine the maximum and minimum density of the sand. At the maximum density, it is determined that the void ratio is 0.35 at the minimum density, the void ratio is 0.95. A. Compute the void ratio of the sand. B. Compute the relative density of the undisturbed sample. C. Compute the dry density in Mg/m³.
3-8 A 1-ft3 of undisturbed soil sample has a dry weight of 107 lbs. The specific gravity of the soil solids is 2.70. Need Vs VT = 1 To solve for Vs = use the following equation Ws=Vs*Gs*yw (solve for Vs) a) Calculate the void ratio of the sample. b) Calculate the porosity of the sample. DC
Problem Set 2: 4. A sample of gray silty clay has a mass of 126 kg. Laboratory tests results give a moist density (p) of 2.05 g/cm³, a specific gravity of solids (G,) of 2.71, and a moisture content (w) of 15.7%. First determine all entries in the phase diagram. Then determine the void ratio (e), the porosity (n), the degree of saturation (S), the dry density (Pa), the dry unit weight (ya), and the moist unit weight (y). Draw the Phase diagram.
OMC-Proctor's Test A sample of dry sand has a volume of 1000 ml in its natural state. Its minimum volume when compacted is 750 ml. When gently poured into a measuring cylinder, its possible maximum volume is 1320 ml. what is the relative density?
Q # 1. Organic soils are typically characterized by high void ratio, low specific gravity, and high compressibility. Following are the results of a consolidation test on a sample of organic soil. Pressure, o (kN/m2) Change in dial reading, AH (mm) 0.284 12 0.150 24 0.315 48 0.564 100 0.823 200 2.25 400 5.34 Given that the initial height of the specimen = 20.6 mm, mass of dry specimen = 12 g, area of specimen = 31.67 cm2 and G, = 2.49. Plot the e, log o' curve. b. Determine the preconsolidation pressure. a.

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