The detailed results of a standard Proctor test on a soilclassified as CL-ML and group name silty clay with sand areshown in the table below. Determine the maximum dry unit.weight and optimum water content.Diameter of mould = 4 inHeight of mould = 4.584 in.Volume of mould 1/30 ft3.Weight of mould, M = 4.45 lbUnit weight dataWater content dataMass of can andWeight of wet soiland mold (Ibs)Mass of can(grams)Mass of can andwet soil (grams)dry soil (grams)MM..M.M.111.48155.087.32114.9246.50163.12190.43193.137.5746.437.687.74178.6446.20178.2446.507.65188.77171.5846.10

Vulume of the mould V=13 ft3=943.89 cm3mass of water =mass of cane and wet soil Mw-mass of cane and…

The detailed results of a standard Proctor test on a soil classified as CL-ML and group name silty clay with sand are shown in the table below. Determine the maximum dry unit .weight and optimum water content .Diameter of mould = 4 in .Height of mould = 4.584 in

The detailed results of a standard Proctor test on a soil classified as CL-ML and group name silty clay with sand are shown in the table below. Determine the maximum dry unit .weight and optimum water content .Diameter of mould = 4 in .Height of mould = 4.584 in

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: 0.1.A A soil specimen have void ratio (e) of 0.7, Gs 2.72. Calculate the total unit weight, dry unit…

A: A) Given that soil specimen is having Void ratio (e) = 0.7 Specific Gravity (Gs) = 2.72 Degree of…

Q: A sample of soil was tested in the laboratory, and the test results were listed as follows. Classify…

Q: ç carefully added to the container so as not to d the container is filled the combined weight…

Q: A cylindrical specimen of a cohesive soil of 13 cm diameter and 20 cm length was prepared by…

Q: What is the maximum weight of the soil sample? B. What is the minimum weight of the soil sample?…

A: GEO TECHNICAL ENGINEERING:

Q: а. Determine the maximum dry unit weight and the optimum water content. b. Plot the zero air voids…

A: Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

Q: 6.41 The results of a standard Proctor test are given in the following table. a. Determine the…

Q: An undisturbed sample of fine sand is tested in the laboratory and found to have a dry mass of 3.23…

Q: A soil layer with a moisture content of 10 percent and a unit weight of 16.5 KN per cubic meter…

A: Question b) Objective: To determine the dry specific weight of the soil (γd,compaction). Given:…

Q: A liquid limit test on a clay was performed with the following results. The natural water content of…

Q: f dr

A: According to given data inorganic clay has a volume of 21.4 cm3 and weighs 36.7 g. After drying,…

Q: 5. Follow ing is the result of a modified proctor test. Determine the maximum dry unit weight, void…

Q: Problem 1: The table below present the results of a standard proctor test of a borrow pit soil. Mass…

A: NOTE : AS per company guidelines, we are obliged to answer only one question at a time. Please ask…

Q: Undisturbed soil sample was collected from the filed in Melbourne in steel tube for laboratory…

A: Diameter of the steel tube = 85 mmLength of steel tube= 170 mm (0.17 m)Moisture weight = 1600…

Q: A hydrometer test was conducted on the material passing sieve No. 200 and the results are listed in…

A: The flow of fluid includes movement of an unbalanced fluid. As long as unequalled forces are in…

Q: The laboratory test on a soil sample yields the following results natural moisture content = 18%,…

Q: The following results were obtained from a liquid limit test on a soil using a liquid limit device.…

Q: TABLE 2 RESULTS OF ORI TEST Water Content (%) Weight (Kg) 14 1.45 16.5 1.71 18.5 1.87 20 1.88 21…

Q: pand cone equipment is Used to perform field density test on a compacted arth fill Soil sample dug…

A: Weight of soil=19.88N Weight of dry soil=17.92N

Q: B. ( A Soil Specimen has the following characteristics. % passing No.4 sieve = 85 % passing No.200…

A: Given, LL = 36% PL = 31%

Q: The natural water content and in-situ unit weight of a sample of sand above water table are 14% and…

A: Given data : Void ratio in densest state emin=0.48 Void ratio in loosest state emax=0.80 Water…

Q: 1. The Void Ratio of a soil sample is 0.54, with a water content of 8% and the specific gravity of…

A: Given data, Void ratio of soil sample= e = 0.54 Water content= w= 8% G= 2.69 Porosity= n= ?

Q: A sample of field soil is tested in the laboratory. The results of Standard and Modified Proctor…

A: ASKED: To compute: degree of compaction/relative compaction (R%) at Standard Proctor Test degree of…

Q: A cylindrical specimen of a cohesive soil of 11 cm diameter and 22 cm length was prepared by…

A: solution Given dia of the sample d=11cm =0.11m radius r=0.11/2=0.055length of the sample L…

Q: Determine the degree of saturation in percentage in a bulk density determination procedure on a…

Q: A soil sample has a porosity of 40 percent. The specific gravity of solids is 2.70. What is voids…

A: This question is related with geotechnical engineering . In this question we are provided with value…

Q: A sample of field soil is tested in the laboratory. The results of Standard and Modified Proctor…

A: The ratio of field dry density to maximum dry density ( density corresponding to optimum moisture…

Q: A 443 gram, 42.8 mm diameter by 97 mm long clay specimen was tested in a triaxial test. After…

Q: a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After…

Q: In order to determine the relative density of a sand sample, its natural moisture content and bulk…

Q: A compaction test was conducted in the laboratory and the following information was obtained: • The…

A: The process in which stress is applied to the soil to densify the mass and remove the air entrapped…

Q: A sand sample has a porosity of 30% and specific gravity of solids as 2.6. What is its degree of…

A: given- porosity n=30%G=2.6moisture content w=4.94%

Q: A sand sample has a porosity of 30% and specific gravity of solids as 2.6. What is its degree of…

A: Given data Porosity (n) = 30% = 0.3 Specific gravity of solid (Gs) = 2.6 Mositure content (w) =…

Q: explain the consistency condition of the soil at site.

A: Consistency Index Formula is given by Consistency Index=WL-WNIp where, WL=Liquid Limit (LL)…

Q: a constant mass of 348 grams. Using either an assumed spec (whichever is more appropriate), FIND the…

A: A)Given data- Weight of soil (Ws) = 469 gms Weight of dry soil (Wd) = 348 gms Diameter of specimen…

Q: Diaz (1992) reported the following values for Mexico City clay: void ratio (e) = 2, natural water…

A: To compute the remaining quantities entering a phase diagram, we can use the following formulas:1.…

Q: The following results were obtained from a liquid limit test on a soil using a liquid limit device.…

Q: A natural soil deposit is to be used for a geotechnical engineering project. Laboratory test results…

A: Soil Properties % Passing Sieve No. 4 (4.75mm) = 100 % % Passing Sieve No. 200 (75μm) = 8 %…

Concept explainers

Soil Compaction Test

Soil compaction is the major area of geotechnical engineering. Soil is composed of multiple pores present on its surface, while the soil is mainly composed of gravel, sand, rocks, etc. The arrangement of these rocks and gravels is such that they build up voids (spaces) between them, which allows spaces for the roots of the plants and crops to spread and absorb the required amount of nutrients. Soil compaction is a major problem primarily caused by human activities, micro-organisms, and other multiple factors.

Question

The detailed results of a standard Proctor test on a soil
classified as CL-ML and group name silty clay with sand are
shown in the table below. Determine the maximum dry unit
.weight and optimum water content
.Diameter of mould = 4 in
Height of mould = 4.584 in
.Volume of mould 1/30 ft3
.Weight of mould, M = 4.45 lb
Unit weight data
Water content data
Mass of can and
Weight of wet soil
and mold (Ibs)
Mass of can
(grams)
Mass of can and
wet soil (grams)
dry soil (grams)
M
M..
M.
M.
111.48
155.08
7.32
114.92
46.50
163.12
190.43
193.13
7.57
46.43
7.68
7.74
178.64
46.20
178.24
46.50
7.65
188.77
171.58
46.10

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1 Solution

VIEW

Step 2 dry densities

VIEW

Step 3 Maximum dry density

VIEW

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

In a sieve analysis test, 95.5% of the sample is passing the 5mm sieve and 5.13% is passing sieve #200, which of the following is correct about this sample: There is no clay in the sample the percent of silt and clay is: 5.13% There is 4.5% Sand and Gravel in the sample 95.5% of the sample is Sand and Silt
a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After adding some water, the degree of saturation was altered to 53%. take the specific gravity of the soil solids to be 2.7. assuming no change in the volume of the voids, determine the following A. void ratio B. water content% C. bulk specific gravity of the mass of the sample in the altered state.
Determine the Fineness Modulus of the sand given its sieve analysis in the following table. (round to 2nd decimal place) Weight Retained Sieve (g) 3/8 in. 10 No.4 80 No.8 80 No.16 350 No.30 240 No.50 80 No.100 160
i need the answer quickly
Hello can any one help me with this
A liquid limit test on a clay was performed with the following results. The natural water content of the clay is 38% and plastic limit is 21%. Number of Blows 6 12 20 28 32 Water content (%) 52.5 47.1 42.3 38.6 37.5 What is the liquid limit of this clay? (Use Interpolation) Group of answer choices 39.85% 39.99% 36.74% 38.63% Please answer this asap for upvote. Thanks
A soil specimen has a total volume of 70 cm3 and a total mass of 135.5g. After complete drying in an oven, the specimen has a mass of 122.0g. The Gs is 2.60. Determine the void ratio. Report your answer to three significant figures, and draw the full phase diagram.
The wet weight of a soil specimen is 207 g. The dried weight of the specimen is 163 g. If the volume of the specimen is measured before drying is 110 cubic centimeter, determine the Void ratio if specific gravity of solids is 2.68.
05: The Figure below represents the data that was obtained from a liquid-limit test on a soil. 50 percent of its particles is passing sieve #200. Two determinations for the plastic limit gave water contents of 20.3 % and 20.8 %. Determine 1- Liquid Limit (LL). 2- Plasticity index. 3- Liquidity index if the water content is 27.4% 4- Void ratio at the liquid limit, if G, 2.7 5- Classify the soil based on AASHTO system. 30 10 20 40 60 80 100 Penetration, d (mm) Moisture content, w ()
Pampanga sand with Gs =2.41 is mixed 16% by weight of water and compacted to produce a cylindrical sample of 50 mm diameter and 100 mm long with 2% air porosity. Calculate the void ratio of the sample.
Sr B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30=0.35 mm D₁0 = 70 μm D8=2 μm L.L = 36% P.L = 31% 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if wc = 26%.