4. Childhood participation in sports, cultural groups,and youth groups appears to be related to improvedself-esteem for adolescents (McGee, Williams,Howden-Charman, Martin, & Kawachi, 2006). Ina representative study, a sample of n = 100 adoles-cents with a history of group participation is givena standardized self-esteem questionnaire. For thegeneral population of adolescents, scores on thisquestionnaire form a normal distribution with a mean%3D%3Dof µ = 50 and a standard deviation of o = 15. The%3D sample of group-participation adolescents had anaverage of M = 53.8.a. Does this sample provide enough evidence to con-clude that self-esteem scores for these adolescentsare significantly different from those of the generalpopulation? Use a two-tailed test with a = .05.b. Compute Cohen's d to measure the size of thedifference.c. Write a sentence describing the outcome of thehypothesis test and the measure of effect size as itwould annear in a research report.

Answered: sample of group-participation…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A male and a female Judge rated the same cartoon segments for violent content. Using the data below, determine whether there is a significant tendency for the female judge to give higher ratings than the male judge. Use a one tailed test at the .05 significance level. Show your work through each step Cartoon segment Male Judge Female Judge 1 2 4 2 1 2 3 8 7 4 0 1 5 2 5 6 7 9 Calculate Cohens d or argue why its not appropriate in this…
Question #2 A diet guide claims that you will get 120 calories in a serving of vanilla yogurt. Consumer Reports tested 14 brands of vanilla yogurt and found the following numbers of calories per serving: 160 200 220 230 120 180 140 130 170 190 80 120 100 170 Test the claim that the mean number of calories per serving of vanilla yogurt is 120. Use a significance level of 0.05. Show all the steps of your hypothesis test including The claim being tested: The null and alternative hypothesis: The test statistic
The mean number of sick days an employee takes per year is believed to be about 10. Members of a personnel department do not believe this figure. They randomly survey 8 employees. The number of sick days they took for the past year are as follows: 10; 5; 13; 3; 11; 8; 6; 9. Let X = the number of sick days they took for the past year. Should the personnel team believe that the mean number is about 10? Conduct a hypothesis test at the 5% level.Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) What is the test statistic? (If using the z distribution round your answers to two decimal places, and if using the t distribution round your answers to three decimal places.) t = Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence…
Suppose a study reported that the average persin watched 3.37 hours of television per day. a random sample of 15 people gave the number of hours of television watched per day shown below. at the 1% significance level, do the data provide sufficent evidence to conclude that the amount of television watched per day last year by the average person is greater than the value reported in the study? what is the test statistic value for this problem? a.0.28 b.-38 c.none of the above d. 0.58 e.-4.295 f..04 g. 1.94 . the proper conclusion for this problem is? a. reject the null hypothesis we have sufficent evidence to prove the average number of hours people watch tv is more than 3.37 hours. b. Do not reject the null hypothesis we have sufficient evidence to prove the average number of hours of TV watched is greater than 3.37 hours c. Reject the null hypothesis and claim the average number of hours people watch TV is less than 3.37 because the P value is near zero d. Do not reject the null…
20
Each person in random samples of 227 male and 293 female working adults living in a certain town in Canada was asked how long, in minutes, his or her typical daily commute was. Is there enough evidence to show that there is a difference in mean commute times for male and female working residents of this town? (Use males females) Male Female Sample size X S Sample size x S 227 30.2 24.0 293 27.9 24.3 Find the test statistic. (Round your answer to two decimal places.) Find the df. (Round your answer down to the nearest whole number.) df= Use technology to find the P-value. (Round your answer to four decimal places.) P-value= Is there enough evidence to show that there is a difference in mean commute times for male and female working residents of this town? Use a significance level of 0.05. Yes No
The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
ANSWER LETTER D,E,F only
Please answer everything. Thank you!
A sociologist believed that the average family size in Saskatchewan was larger than the average family size in British Columbia. Random samples from the two provinces yielded the following results: s? Saskatchewan (Pop 1) British Columbia (Pop 2) 3.45 1.34 60 2.89 1.32 52 Test at a = 0.05 whether there is sufficient evidence to support the claim. As well, calculate the p-value for this test.
Question 2 > The average number of cavities that thirty-year-old Americans have had in their lifetimes is 7. Do twenty- year-olds have a different number of cavities? The data show the results of a survey of 14 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 7, 8, 7, 7, 9, 7, 10, 9, 8, 10, 6, 9, 6, 8 What can be concluded at the a = 0.05 level of significance? %3D a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: |? Select an answer H1: Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that . The data suggest the populaton mean is significantly different from 7 at a = 0.05, so there is sufficient evidence to conclude that the…
. Test the claim that the mean age of the prison population in one city is less than 26 years. Sample data are summarized as n=25, x=24.4, s=9.2. Use a significance level of a=0.05 Null and alternative hypothesis (give both in symbolic form and sentence form): Test statistic and p-value (show the calculation or show what you entered into the calculator (screenshots are ok here)): Technical conclusion, circle one: reject the null hypothesis or fail to reject the null hypothesis Why did you choose to reject or fail to reject the null hypothesis? Nontechnical conclusion addressing the original claim:

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