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- Interpret In (AVR) = In (AV) -t as y(t)=b+mt T and get the result: graph of In (AVR) versus / (called a semi-log graph) should be linear with y-intercept b = ln (AV) and slope m = 1 =-²/ T We can determine t and hence C from an experimental measurement of the slope. Draw a graph of In (AVR) (log of measured voltage across the resistor, vertical axis) vs time (horizontal axis). From the y-intercept of the best-fit line, find AVo = 9[V], as expected. Using the slope, find T = Using this calculate the unknown capacitance: T Cexperimental R - - 1 slope = Now, measure the actual value of the capacitance with the digital multimeter and compare it to the value obtained from the graph: Actual capacitance is: 12,4 FIa metal is heated, its atoms vibrate more when about their position in the lattice (a netuons of crossed burs) This Causes them to take up more Space, so the solid metal expands from its original shape. calculate the heat needed to expand a ring made of copper internal diameter of Somm to fit over a Shaft of with an diameter So.05mm. The shaft is measured at a temp 182Solve the following differential equations. You may have to leave your answer implicit. 1) y'=(y-4x)/(x-y) is it isobaric? 2) x(1+y2)y'+x2y3=0 hint: try the integrating factor λ(x)= 1/xy3
- 1.1 An old lightbulb draws only 108.5 W, rather than its original 120 W, due to evaporative thinning of its filament. By what factor is its diameter reduced, assuming uniform thinning along its length? Neglect any effects caused by temperature differences. dold doriginal +Suppose that the floating point component of a processor is upgraded so that each floating point instruction takes only 1/4 as much time to execute as previously. (The execution times of all other types of instructions remain unchanged.) If the upgrade decreases the execution time of a particular program to 0.7 times what it was originally, what fraction of the original execution time must have been spent on executing floating point instructions? (Give your answer as a decimal number to at most two decimal places, e,g, 0.13.)Ohms