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Advanced Physics
13 A strip of copper 150 μm thick and 4.5 mm wide is placed in a uniform magnetic field B of magnitude 0.65 T, with B perpendi- cular to the strip. A current i = 23 A is then sent through the strip such that a Hall potential difference V appears across the width of the strip. Calculate V. (The number of charge carriers per unit vol- ume for copper is 8.47 X 1028 electrons/m³.)

13 A strip of copper 150 μm thick and 4.5 mm wide is placed in a uniform magnetic field B of magnitude 0.65 T, with B perpendi- cular to the strip. A current i = 23 A is then sent through the strip such that a Hall potential difference V appears across the width of the strip. Calculate V. (The number of charge carriers per unit vol- ume for copper is 8.47 X 1028 electrons/m³.)

Question
In problem 13, solve for the Hall voltage (in microVolts) that would be generated if 8.1 Amperes of current are used to probe the material. 5 sig figs
**Question 3** In problem 28.13, solve for the Hall voltage (in microVolts) that would be generated if 8.1 Amperes of current are used to probe the material. Please ensure your answer is accurate to 5 significant figures. [Answer box for input]
Transcribed Image Text:**Question 3** In problem 28.13, solve for the Hall voltage (in microVolts) that would be generated if 8.1 Amperes of current are used to probe the material. Please ensure your answer is accurate to 5 significant figures. [Answer box for input]
**Module 28-3: Crossed Fields: The Hall Effect** **13** A strip of copper 150 μm thick and 4.5 mm wide is placed in a uniform magnetic field \(\mathbf{B}\) of magnitude 0.65 T, with \(\mathbf{B}\) perpendicular to the strip. A current \(i = 23 \, \text{A}\) is then sent through the strip such that a Hall potential difference \(V\) appears across the width of the strip. Calculate \(V\). (The number of charge carriers per unit volume for copper is \(8.47 \times 10^{28} \, \text{electrons/m}^3\).)
Transcribed Image Text:**Module 28-3: Crossed Fields: The Hall Effect** **13** A strip of copper 150 μm thick and 4.5 mm wide is placed in a uniform magnetic field \(\mathbf{B}\) of magnitude 0.65 T, with \(\mathbf{B}\) perpendicular to the strip. A current \(i = 23 \, \text{A}\) is then sent through the strip such that a Hall potential difference \(V\) appears across the width of the strip. Calculate \(V\). (The number of charge carriers per unit volume for copper is \(8.47 \times 10^{28} \, \text{electrons/m}^3\).)
Expert Solution
Step 1

It is given that,

  • the thickness of copper is t=150 μm=150×10-6 m
  • the width of copper ω=4.5 mm=4.5×10-3 m
  • Magnetic field B=0.65 T
  • Current i=23 A
  • number of charge carriers per unit volume is n=8.47×1028 electron/m3

It is required to calculate the hall voltage across the width of the strip. 

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