Experime Time [s] 3 no 6 а 12 15 18 21 24 29 Data (discharging): 35 Voltage across the resistor, AVR [v] 5.9 4.3 3.1 2,3 ما .ا 1.2 0.8 0.6 0.4 0,2 In (AVR)
Experime Time [s] 3 no 6 а 12 15 18 21 24 29 Data (discharging): 35 Voltage across the resistor, AVR [v] 5.9 4.3 3.1 2,3 ما .ا 1.2 0.8 0.6 0.4 0,2 In (AVR)
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Question
![Experim
Time
[s]
3
na 6
ait
12
15
18
21
24
29
35
Ischarging):
Voltage across the
resistor, AVR [v]
5.9
4.3
byly 3,1
2,3
1.6
1.2
0.8
0.6
0.4
0,2
In (AVR)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F50351a65-5e52-4545-9e5a-caf58e03b0d0%2Fb23280ca-5bde-4443-8427-423ae39eca37%2Fhupd6yi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Experim
Time
[s]
3
na 6
ait
12
15
18
21
24
29
35
Ischarging):
Voltage across the
resistor, AVR [v]
5.9
4.3
byly 3,1
2,3
1.6
1.2
0.8
0.6
0.4
0,2
In (AVR)
![Interpret
In (AVR) = In (AV) -t as y(t)=b+mt
T
and get the result: graph of In (AVR) versus / (called a semi-log graph) should be linear
with y-intercept b = ln (AV) and slope m =
1
=-²/
T
We can determine t and hence C from an experimental measurement of the slope.
Draw a graph of In (AVR) (log of measured voltage across the resistor, vertical axis)
vs time (horizontal axis).
From the y-intercept of the best-fit line, find AVo = 9[V], as expected.
Using the slope, find T =
Using this calculate the unknown capacitance:
T
Cexperimental R
-
-
1
slope
=
Now, measure the actual value of the capacitance with the digital multimeter and
compare it to the value obtained from the graph:
Actual capacitance is: 12,4
FI](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F50351a65-5e52-4545-9e5a-caf58e03b0d0%2Fb23280ca-5bde-4443-8427-423ae39eca37%2Fq9ftf1c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Interpret
In (AVR) = In (AV) -t as y(t)=b+mt
T
and get the result: graph of In (AVR) versus / (called a semi-log graph) should be linear
with y-intercept b = ln (AV) and slope m =
1
=-²/
T
We can determine t and hence C from an experimental measurement of the slope.
Draw a graph of In (AVR) (log of measured voltage across the resistor, vertical axis)
vs time (horizontal axis).
From the y-intercept of the best-fit line, find AVo = 9[V], as expected.
Using the slope, find T =
Using this calculate the unknown capacitance:
T
Cexperimental R
-
-
1
slope
=
Now, measure the actual value of the capacitance with the digital multimeter and
compare it to the value obtained from the graph:
Actual capacitance is: 12,4
FI
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