Table 3(Resistors in both series and parallel) R(Q) ¡ex(A) R₁ R₂ R3 R4 Reg 10Ω 100Ω 1000 10Ω 10 100 100 10 0.0175 0.0165 0.0165 0.0017 0.0135 Vex(V) ith(A) 2.006 0.171 1.641 0.173 0.153 Vth(V) % Error i % Error V 7. Using the equations for resistors in series and in parallel, calculate the theoretical voltages and currents for each of the resistors, and the entire circuit. Use the measured values of resistance in your calculations, then calculate the % errors. Show work.

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The circuit diagram illustrates a simple electrical circuit containing a battery and four resistors labeled R1, R2, R3, and R4. 

- The battery, depicted on the left side, provides the voltage for the circuit.
- Resistor R1 is connected in series with resistor R2.
- The combination of resistors R1 and R2 in series is followed by a parallel configuration of resistors R3 and R4.
- The parallel resistors share the same two nodes and are connected across each other.

This type of circuit is useful for understanding basic principles of series and parallel resistance in electrical circuits. In series, the total resistance is the sum of R1 and R2. For resistors in parallel, such as R3 and R4, the total resistance can be calculated using the formula: 

\[ \frac{1}{R_{\text{total}}} = \frac{1}{R3} + \frac{1}{R4} \]

These principles are fundamental in designing and analyzing electrical circuits.
Transcribed Image Text:The circuit diagram illustrates a simple electrical circuit containing a battery and four resistors labeled R1, R2, R3, and R4. - The battery, depicted on the left side, provides the voltage for the circuit. - Resistor R1 is connected in series with resistor R2. - The combination of resistors R1 and R2 in series is followed by a parallel configuration of resistors R3 and R4. - The parallel resistors share the same two nodes and are connected across each other. This type of circuit is useful for understanding basic principles of series and parallel resistance in electrical circuits. In series, the total resistance is the sum of R1 and R2. For resistors in parallel, such as R3 and R4, the total resistance can be calculated using the formula: \[ \frac{1}{R_{\text{total}}} = \frac{1}{R3} + \frac{1}{R4} \] These principles are fundamental in designing and analyzing electrical circuits.
**Table 3: Resistors in both series and parallel**

|     | R(Ω)  | \(i_{ex}(A)\) | \(V_{ex}(V)\) | \(i_{th}(A)\) | \(V_{th}(V)\) | % Error \(i\) | % Error \(V\) |
|-----|-------|---------------|---------------|---------------|---------------|---------------|---------------|
| \(R_{eq}\) | 0.0175 | 2.006  |               |               |           |               |
| \(R_1\)    | **10Ω**  | 10      | 0.0165        | 0.171         |               |               |               |
| \(R_2\)    | **100Ω** | 100     | 0.0165        | 1.641         |               |               |               |
| \(R_3\)    | **100Ω** | 100     | 0.0017        | 0.173         |               |               |               |
| \(R_4\)    | **10Ω**  | 10      | 0.0135        | 0.153         |               |               |               |

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7. **Instructions**: Using the equations for resistors in series and parallel, calculate the theoretical voltages and currents for each of the resistors, and the entire circuit. Use the measured values of resistance in your calculations, then calculate the percentage errors. Show work.
Transcribed Image Text:**Table 3: Resistors in both series and parallel** | | R(Ω) | \(i_{ex}(A)\) | \(V_{ex}(V)\) | \(i_{th}(A)\) | \(V_{th}(V)\) | % Error \(i\) | % Error \(V\) | |-----|-------|---------------|---------------|---------------|---------------|---------------|---------------| | \(R_{eq}\) | 0.0175 | 2.006 | | | | | | \(R_1\) | **10Ω** | 10 | 0.0165 | 0.171 | | | | | \(R_2\) | **100Ω** | 100 | 0.0165 | 1.641 | | | | | \(R_3\) | **100Ω** | 100 | 0.0017 | 0.173 | | | | | \(R_4\) | **10Ω** | 10 | 0.0135 | 0.153 | | | | --- 7. **Instructions**: Using the equations for resistors in series and parallel, calculate the theoretical voltages and currents for each of the resistors, and the entire circuit. Use the measured values of resistance in your calculations, then calculate the percentage errors. Show work.
Expert Solution
Step 1

Given,

R1=10ΩR2=100ΩR3=100ΩR4=10Ω

The equivalent resistance, 

Req=R1+R2+R3R4R3+R4Req=10+100+10×100110Req=119.09Ω

The total current in the circuit,

ieq=VReqieq=2.006119.09ieq=0.0168A

ith1=ith2=ieq=0.0168A

ith3=0.0168×10100+10ith3=0.0168×10100+10ith3=0.00152Aith4=0.0168×100100+10ith4=0.0152A

Vth1=ith1R1Vth1=0.0168×10Vth1=0.168VVth2=ith2R2Vth2=0.0168×100Vth2=1.68V

Vth3=ith3R3Vth3=0.00152×100Vth3=0.152VVth4=ith4R4Vth4=0.0152×10Vth4=0.152V

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