Explain the answers 6. The capacitor Cs is removed from the circuit in Figure 1. Derive a new expression forthe voltage gaiìn and determine its numerical value.VDDVDD = 3 VR1 = 4kS RDR1R2 = 5kC2C1M1outRD = 5kin HHRS = 6kRext 20kRextCsR2RSovFigure 1VDDVDD = 3 VR1 = 4kR1 3R2 = 6kC1RS = 1kM1in HEC2outR2RSRexdovFigure 2VDD = 2 VVSS = 0 VRD2 = 4kRD1RD2RS2 = 6kR12M2R1 = 4kM1R2 = 4kRD1 = 4kVOUTV1RS1 = 4kVINR2RS12 CS1=RS2Cs2Figure 3VDD = 2 VRS2 = 6kVDDVSS = 0 VRI = 4kR2 = 4kSRD1R1M2VinM1RD1 = 4kbutRS1 = 4kVoutR2{ RS1 Tcs RS2'Vss = 0 VFigure 4 6. The capacitor Cs is removed from the circuit in Figure 1New small-signal equivalent circuit:iinVgsgmVgsRGVoutVinRDRSVsRs modifies circuit substantially – it cannot be ignored now. Simplify analysis by neglectingr. (which we know to be big anyway). Simplified circuit is:linVgs9mVgsRGVoutVin: RDRS {VsVin =Vgs + v,in dudiny to 05 m gs+ Dout -UsVout =-8mR,V gsv, = 8mRsV gs-Coml imueVoutG =V in%3DVes + 8mRsV es 1+ 8„RsThe effect of Rs is to reduce the gain (undesirable). Detailed analysis shows that Rs developsnegative feedback in the circuit, and phenomenon is called source degeneration. Sometimesit is employed deliberately in small amounts to make circuits more stable and resistant tocomponent value variation. In the limit Rs → 0, then Gy = -gmRp as per the lecture notes.Numerically G, = -(1.72*5)/(1 + 1.72*6) = -0.76NB – for gmRs >> 1, G, → Rp/Rs.

Given : In the above question they want to know about the question Figure 1 . Here they want to…

ro (which We RHOW in Vgs 9mVgs RG Vout RD Vin RS Vs Vin =Vgs + v, ndudingco Vout-Us 2 Vouu =ー8mR v, = 8mRsV gs -Comd imue V out G = Vin Vgs + 8mRsV es 1+ g„Rs The effect of Rs is to reduce the gain (undesirable). Detailed analysis shows that Rs develops negative feedback in the circuit, and phenomenon is called source degeneration. Sometimes it is employed deliberately in small amounts to make circuits more stable and resistant to component value variation. In the limit Rs → 0, then Gy = -gmRp as per the lecture notes. Numerically G, = -(1.72*5)/(1 + 1.72*6) = -0.76 NB - for gmRs >> 1, G, →Rp/Rs.

ro (which We RHOW in Vgs 9mVgs RG Vout RD Vin RS Vs Vin =Vgs + v, ndudingco Vout-Us 2 Vouu =ー8mR v, = 8mRsV gs -Comd imue V out G = Vin Vgs + 8mRsV es 1+ g„Rs The effect of Rs is to reduce the gain (undesirable). Detailed analysis shows that Rs develops negative feedback in the circuit, and phenomenon is called source degeneration. Sometimes it is employed deliberately in small amounts to make circuits more stable and resistant to component value variation. In the limit Rs → 0, then Gy = -gmRp as per the lecture notes. Numerically G, = -(1.725)/(1 + 1.726) = -0.76 NB - for gmRs >> 1, G, →Rp/Rs.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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