Richard observes that a single slit that is2,022 nm wide forms a diffraction pattern when illuminated by monochromatic light of673 -nm wavelength. At an angle of 10° from the central maximum, what is the ratio of the intensity to the intensity of the central maximum? Give your answer with two decimal places please.

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### Diffraction Pattern Analysis

**Problem Statement:**
Richard observes that a single slit that is 2,022 nm wide forms a diffraction pattern when illuminated by monochromatic light of 673 nm wavelength. At an angle of 10° from the central maximum, what is the ratio of the intensity to the intensity of the central maximum? Give your answer with two decimal places, please.

**Solution:**

To determine the ratio of the intensity at an angle (θ) to the intensity at the central maximum for a single slit diffraction pattern, we use the diffraction intensity formula:

\[ I(\theta) = I_0 \left(\frac{\sin(\beta/2)}{\beta/2}\right)^2 \]

where:
- \( \beta = \frac{2 \pi a \sin(\theta)}{\lambda} \)
- \( a \) is the width of the slit
- \( \lambda \) is the wavelength of the light
- \( \theta \) is the angle from the central maximum
- \( I_0 \) is the central maximum intensity.

Given:
- \( a = 2022 \) nm
- \( \lambda = 673 \) nm
- \( \theta = 10° \)

We first calculate \( \beta \):

\[ \beta = \frac{2 \pi \times 2022 \times \sin(10°)}{673} \]

\[ \sin(10°) \approx 0.1736 \]

\[ \beta = \frac{2 \pi \times 2022 \times 0.1736}{673} \]

\[ \beta \approx \frac{2201.584 \times 0.1736}{673} \]

\[ \beta \approx 0.5699 \]

Now plug \( \beta \) into the intensity formula:

\[ I(\theta) = I_0 \left(\frac{\sin(0.5699/2)}{0.5699/2}\right)^2 \]

\[ I(\theta) = I_0 \left(\frac{\sin(0.28495)}{0.28495}\right)^2 \]

\[ \sin(0.28495) \approx 0.2810 \]

\[ I(\theta) = I_0 \left(\frac{0.2810}{0.28495}\right)^2 \]

\[ \
Transcribed Image Text:### Diffraction Pattern Analysis **Problem Statement:** Richard observes that a single slit that is 2,022 nm wide forms a diffraction pattern when illuminated by monochromatic light of 673 nm wavelength. At an angle of 10° from the central maximum, what is the ratio of the intensity to the intensity of the central maximum? Give your answer with two decimal places, please. **Solution:** To determine the ratio of the intensity at an angle (θ) to the intensity at the central maximum for a single slit diffraction pattern, we use the diffraction intensity formula: \[ I(\theta) = I_0 \left(\frac{\sin(\beta/2)}{\beta/2}\right)^2 \] where: - \( \beta = \frac{2 \pi a \sin(\theta)}{\lambda} \) - \( a \) is the width of the slit - \( \lambda \) is the wavelength of the light - \( \theta \) is the angle from the central maximum - \( I_0 \) is the central maximum intensity. Given: - \( a = 2022 \) nm - \( \lambda = 673 \) nm - \( \theta = 10° \) We first calculate \( \beta \): \[ \beta = \frac{2 \pi \times 2022 \times \sin(10°)}{673} \] \[ \sin(10°) \approx 0.1736 \] \[ \beta = \frac{2 \pi \times 2022 \times 0.1736}{673} \] \[ \beta \approx \frac{2201.584 \times 0.1736}{673} \] \[ \beta \approx 0.5699 \] Now plug \( \beta \) into the intensity formula: \[ I(\theta) = I_0 \left(\frac{\sin(0.5699/2)}{0.5699/2}\right)^2 \] \[ I(\theta) = I_0 \left(\frac{\sin(0.28495)}{0.28495}\right)^2 \] \[ \sin(0.28495) \approx 0.2810 \] \[ I(\theta) = I_0 \left(\frac{0.2810}{0.28495}\right)^2 \] \[ \
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