The single slit experiment was carried out using light having a wavelength of 500 nm, perpendicular to the 5 µm wide slit. The distance between the screen and the gap is 3.5 m. Calculate the distance between the center diffraction pattern and the minimum second diffraction
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The single slit experiment was carried out using light having a wavelength of 500 nm, perpendicular to the 5 µm wide slit. The distance between the screen and the gap is 3.5 m. Calculate the distance between the center diffraction pattern and the minimum second diffraction
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- Interference by a double slit With:- red diode laser λred = (650 ± 20)nm and green λgreen = (532 ± 20)nm:- double slots d=(0.25 ± 0.01)mm with a = (0.080 ± 0.005)mm on a support;- double slots d =(0.50 ± 0.01)mm with a = (0.080 ± 0.005)mm on a support;- Screen wall, white sheet and masking tape;- ruler;- Tape measure;- computer to perform linear regression in a computer Establish the relevant theoretical model:Write an equation relating the distance between the two slits (d), the wavelength of the light source (λ), the distance from the screen (L), the linear position (y) of the bright interference fringes and the order of these fringes (m). Use the small angle approximation. Indicate how to linearize the graph to find the wavelength. Explicitly indicate your choice for the variables X, Y, the slope and the intercept.Light of wavelength 585.5 nm illuminates a slit of width 0.70 mm. (a) At what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0.93 mm from the central maximum? Answer in m (b) Calculate the width of the central maximum. Answer in mmProblem 5: Consider a 525 nm light falling on a single slit of width 1.3 µm. Randomized Variables λ = 525 nm w = 1.3 μm At what angle (in degrees) is the first minimum for the light? 0 = || sin() cos() cotan() asin() atan() acotan() cosh() tanh() O Degrees tan() acos() sinh() cotanh() Radians π () E ^^^ 4 5 1 2 7 8 9 6 3 * + 0 VO BACKSPACE DEL HOME END CLEAR
- In a diffraction experiment the 1st order light (m=1) from a diffraction grating is falling onto a single slit (see picture below). The light from the slit is then observed on a second screen and the measured width of the central diffraction peak is found to be 8 mm. Calculate the number of lines per millimetres of the grating. The distance from the slit to the second screen is 2.16 m, the distance from the diffraction grating to the screen with the slit is 5 m, the slit width is 0.25 mm and the distance from the middle of the screen with the slit to the slit is 10 mm. 一个个个 light Grating Screen with slit Slit of size a distance from middle of Screen to the slit مع Width of Central ✓diffraction peakeThe hydrogen spectrum has a red line at 656 nm and a violet line at 434 nm. What angular separation between these two spectral lines is obtained with a diffraction grating that has 4 500 lines/cm?A red laser (λ = 656 nm) is incident on a diffraction grating that has n = 1100 lines per cm.Randomized Variablesλ = 656 nmn = 1100 lines/cm Part (a) What is the angle, in radians, that the first order maximum makes, θ1? Part (b) What is the angle of the fourth order maximum, θ4, in radians?
- Light of wavelength 588.2 nm illuminates a slit of width 0.63 mm. (a) At what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0.86 mm from the central maximum? (b) Calculate the width of the central maximum. Step 1 (a) As shown in the figure, dark bands or minima occur where sin 0 = m(2/a). For the first minimum, m = 1 and the distance from the center of the central maximum to the first minimum is y₁ = L tan 8, where L is the distance of the viewing screen from the slit. 32 sin dark = 22/a 31 sin dark = λ/a HE 0 -1 sin dark = -λ/a -2 sin dark = -22/a Viewing screen a Because is very small, we can use the approximation tan sin 0 = m(2/a). Substituting the approximation and solving for the distance to the screen, we have 6.3 x 10 m ³ m ) (₁ L = = y ₁ ( ² ) = x 10-3 m x 10-⁹ m m.Coherent microwave light with a frequency f= 2.0*1010 Hz is incident on a d=5.0 cm double slit barrier, producing an interference pattern of a number of maxima and minima. A detector is free to swing around the full 180 degrees in order to find the presence of intereference maxima and minima. How many different minima will this detector detect, as it is allowed to swing around the full 180 degrees? Include minima on both sides of the centerkine in your count.An X-ray beam of wavelength 3.4 × 10-10 m makes an angle of 27° with a set of planes in a crystal which results in first order constructive interference. Determine the plane spacing in nanometers. (Please include 2 decimal places).
- Problem 6: We use 633-nm light from a He-Ne laser to demonstrate Young's double-slit experiment. The interference pattern will be projected on a wall that is 5.0 m from the slits. We want the distance between the m=0 and m=1 maxima to be 25 cm. What slit separation is required to produce the desired interference pattern?An electric current through an unknown gas produces several distinct wavelengths of visible light. Consider the first order maxima for the wavelengths 403 nm, 428 nm, 511 nm, and 682 nm of this unknown spectrum, when projected with a diffraction grating of 5,000 lines per centimeter.Randomized Variablesλ1 = 403 nmλ2 = 428 nmλ3 = 511 nmλ4 = 682 nm Part (a) What would the angle (in degrees) be for the 403 nm line? Part (b) What would the angle (in degrees) be for the 428 nm line? Part (c) What would the angle (in degrees) be for the 511 nm line? Part (d) What would the angle (in degrees) be for the 682 nm line? Part (e) Using this grating, what would be the angle (in degrees) of the second-order maximum of the 403 nm line?In a diffraction experiment the 1st order light (m = 1) from a diffraction grating is falling onto a single slit (see picture below). The light from the slit is then observed on a second screen and the measured width of the central diffraction peak is found to be 8 mm. Calculate the number of lines per millimetres of the grating. The distance from the slit to the second screen is 1.37 m, the distance from the diffraction grating to the screen with the slit is 5 m, the slit width is 0.25 mm and the distance from the middle of the screen with the slit to the slit is 10 mm..