Suppose that Young's experiment is performed with light of wavelength 497 nm. The slits are 1.74 mm apart, and the viewing so is 4.51 m from the slits. How far apart are the bright fringes in meters? Number Units

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A: This problem can be solved using the formula for double slit interference.

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A: Step 1:

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A: It is given that, λ=500 nm=500×10-9ma=5 μm=5×10-6 mD=3.5 m It is required to calculate the distance…

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A: Distance of 7th dark fringe, ym = 0.033m Distance from slit,L=1.1 m Separation b/w slits, d= 1.3 x…

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