Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 42 of the 49 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 74 of the 91 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. test the claim using a nypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? OA. Ho: P₁ P2 H₁: P₁ P₂ D. Ho: P1 P2 H₁: P₁ P₂ Identify the test statistic. 2= 0.66 (Round to two decimal places as needed.) Identify the P-value. P-value 0.509 (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? OB. Ho: P₁ P₂ H₁: P₁ P2 OE. Ho: P SP₂ H₁: P₁ P₂ OC. Ho: P1 P₂ H₁: P1 P₂ OF H₂: P1 P₂ H₁: P1 P₂ The P-value is greater than the significance level of a 0.05, so fail to reject the null hypothesis. There is not sufficient evidence to support the claim that echinacea treatment has an effect. b. Test the claim by constructing an appropriate confidence interval The 95% confidence interval is (P₁-P₂) (Round to three decimal places as needed.)
Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 42 of the 49 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 74 of the 91 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. test the claim using a nypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? OA. Ho: P₁ P2 H₁: P₁ P₂ D. Ho: P1 P2 H₁: P₁ P₂ Identify the test statistic. 2= 0.66 (Round to two decimal places as needed.) Identify the P-value. P-value 0.509 (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? OB. Ho: P₁ P₂ H₁: P₁ P2 OE. Ho: P SP₂ H₁: P₁ P₂ OC. Ho: P1 P₂ H₁: P1 P₂ OF H₂: P1 P₂ H₁: P1 P₂ The P-value is greater than the significance level of a 0.05, so fail to reject the null hypothesis. There is not sufficient evidence to support the claim that echinacea treatment has an effect. b. Test the claim by constructing an appropriate confidence interval The 95% confidence interval is (P₁-P₂) (Round to three decimal places as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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