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Returns the area of the largest rectangle in . The area of a rectangle is defined by number of 1's that it contains.

Returns the area of the largest rectangle in . The area of a rectangle is defined by number of 1's that it contains.

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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using this code(PYTHON):

def longest_chain(lst: list[int]) -> int:
i = 0
answer = []
while i < len(lst) and lst[i] == 1:
answer.append(lst[i])
i += 1
return sum(answer)

 

How do I solve these two questions

def largest_at_position(matrix: list[list[int]], row: int, col: int) -> int: Returns the area of the largest rectangle whose top left corner is at position <row>, <col> in <matrix>, You MUST make use of the helper <longest_chain> here as you loop through each row of the matrix. Do not modify (i.e., mutate) the input matrix. >>> case1 = [[1, 0, 1, 0, 0], [1, 0, 1, 1, 1], [1, 1, 1, 1, 1], [1, 0, 0, 1, 0]] .. >>> largest_at_position(case1, 0, 0) 4 >>> largest_at_position(case1, 2, 0) 5 >>> largest_at_position(case1, 1, 2) 6
Transcribed Image Text:def largest_at_position(matrix: list[list[int]], row: int, col: int) -> int: Returns the area of the largest rectangle whose top left corner is at position <row>, <col> in <matrix>, You MUST make use of the helper <longest_chain> here as you loop through each row of the matrix. Do not modify (i.e., mutate) the input matrix. >>> case1 = [[1, 0, 1, 0, 0], [1, 0, 1, 1, 1], [1, 1, 1, 1, 1], [1, 0, 0, 1, 0]] .. >>> largest_at_position(case1, 0, 0) 4 >>> largest_at_position(case1, 2, 0) 5 >>> largest_at_position(case1, 1, 2) 6
def largest in_matrix(matrix: list[list[int]]) -> int: II II || Returns the area of the largest rectangle in <matrix>. The area of a rectangle is defined by number of 1's that it contains. Again, you MUST make use of the helper <largest_at_position> here. If you managed to code <largest_at_position> correctly, this function should be simple to implement. Similarly, do not modify (i.e., mutate) the input matrix. Precondition: <matrix> will only contain the integers 1 and 0. >>> case1 = [[1, 0, 1, 0, 0], [1, 0, 1, 1, 1], [1, 1, 1, 1, 1], [1, 0, 0, 1, 0]] >>> largest_in_matrix(case1) 6
Transcribed Image Text:def largest in_matrix(matrix: list[list[int]]) -> int: II II || Returns the area of the largest rectangle in <matrix>. The area of a rectangle is defined by number of 1's that it contains. Again, you MUST make use of the helper <largest_at_position> here. If you managed to code <largest_at_position> correctly, this function should be simple to implement. Similarly, do not modify (i.e., mutate) the input matrix. Precondition: <matrix> will only contain the integers 1 and 0. >>> case1 = [[1, 0, 1, 0, 0], [1, 0, 1, 1, 1], [1, 1, 1, 1, 1], [1, 0, 0, 1, 0]] >>> largest_in_matrix(case1) 6
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