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The array contains all 10 different integers. Store them in a linked list in order and print them out.

The array contains all 10 different integers. Store them in a linked list in order and print them out.

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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```cpp #include <iostream> using namespace std; typedef struct node* NodePtr; struct node { public: int data; NodePtr link; }; void print(NodePtr head) { for (NodePtr ptr = head; ptr != NULL; ptr = ptr->link) cout << ptr->data << " "; cout << endl; } ``` ### Explanation: This C++ code defines a simple structure and a function to work with a linked list: 1. **Header and Namespace:** - `#include <iostream>`: This line includes the input-output stream library which is necessary for using `cout`. - `using namespace std;`: This line allows direct access to the standard library objects and functions without prefixing them with `std::`. 2. **Node Structure:** - A node in the linked list is defined using a struct called `node`. - It contains: - `int data;`: An integer to store data. - `NodePtr link;`: A pointer (`NodePtr`) to the next node in the list. 3. **Typedef Declaration:** - `typedef struct node* NodePtr;` creates a type alias `NodePtr` for a pointer to a `node` structure. 4. **Print Function:** - `void print(NodePtr head)`: This function takes the head of the list as an argument and prints each node’s data. - Inside the function, a for-loop iterates through the list until it reaches the end (`NULL`). - `cout << ptr->data << " ";` outputs the data of each node followed by a space. - After the loop, `cout << endl;` outputs a newline character.
Transcribed Image Text:```cpp #include <iostream> using namespace std; typedef struct node* NodePtr; struct node { public: int data; NodePtr link; }; void print(NodePtr head) { for (NodePtr ptr = head; ptr != NULL; ptr = ptr->link) cout << ptr->data << " "; cout << endl; } ``` ### Explanation: This C++ code defines a simple structure and a function to work with a linked list: 1. **Header and Namespace:** - `#include <iostream>`: This line includes the input-output stream library which is necessary for using `cout`. - `using namespace std;`: This line allows direct access to the standard library objects and functions without prefixing them with `std::`. 2. **Node Structure:** - A node in the linked list is defined using a struct called `node`. - It contains: - `int data;`: An integer to store data. - `NodePtr link;`: A pointer (`NodePtr`) to the next node in the list. 3. **Typedef Declaration:** - `typedef struct node* NodePtr;` creates a type alias `NodePtr` for a pointer to a `node` structure. 4. **Print Function:** - `void print(NodePtr head)`: This function takes the head of the list as an argument and prints each node’s data. - Inside the function, a for-loop iterates through the list until it reaches the end (`NULL`). - `cout << ptr->data << " ";` outputs the data of each node followed by a space. - After the loop, `cout << endl;` outputs a newline character.
**Problem 1** - The array contains all 10 different integers. Store them in a linked list in order and print them out. **Array Visualization:** ``` 4 3 4 3 4 6 3 4 6 1 3 4 6 1 10 1 3 4 6 9 10 1 3 4 5 6 9 10 1 3 4 5 6 8 9 10 1 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 ``` **C++ Code:** ```cpp int main() { int A[10] = { 4, 3, 6, 1, 10, 9, 5, 8, 7, 2 }; return 0; } ``` **Explanation of the Task:** - You are given an array consisting of 10 different integers. The task is to store these integers into a data structure called a linked list, where they should be arranged in order. Finally, you are required to print the ordered sequence of integers. **Explanation of the Diagram:** - The diagram on the left visually represents the process of ordering the integers step by step. Each step shows the intermediate ordering of integers as new elements are added: - Starts with adding the integer 4. - Then adds 3 and places it in the correct position before 4. - The process continues, adding each subsequent integer and inserting it into its correct position in the sequence, resulting in a fully ordered sequence by the final step.
Transcribed Image Text:**Problem 1** - The array contains all 10 different integers. Store them in a linked list in order and print them out. **Array Visualization:** ``` 4 3 4 3 4 6 3 4 6 1 3 4 6 1 10 1 3 4 6 9 10 1 3 4 5 6 9 10 1 3 4 5 6 8 9 10 1 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 ``` **C++ Code:** ```cpp int main() { int A[10] = { 4, 3, 6, 1, 10, 9, 5, 8, 7, 2 }; return 0; } ``` **Explanation of the Task:** - You are given an array consisting of 10 different integers. The task is to store these integers into a data structure called a linked list, where they should be arranged in order. Finally, you are required to print the ordered sequence of integers. **Explanation of the Diagram:** - The diagram on the left visually represents the process of ordering the integers step by step. Each step shows the intermediate ordering of integers as new elements are added: - Starts with adding the integer 4. - Then adds 3 and places it in the correct position before 4. - The process continues, adding each subsequent integer and inserting it into its correct position in the sequence, resulting in a fully ordered sequence by the final step.
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