Return this to the familiar linear system 2х1 + х2 — ӕз + 2х4 3x2 – x3 + 2x4 -x3 + 4x4 = 2x4 -1 11 6. Solving by back substitution, we obtain X4 = 3, x3 = 1, x2 = -2, x1 =1
Return this to the familiar linear system 2х1 + х2 — ӕз + 2х4 3x2 – x3 + 2x4 -x3 + 4x4 = 2x4 -1 11 6. Solving by back substitution, we obtain X4 = 3, x3 = 1, x2 = -2, x1 =1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Return this to the familiar linear system
2х1 + х2 — ӕз + 2х4
3x2 – x3 + 2x4
-x3 + 4x4 =
2x4
-1
11
6.
Solving by back substitution, we obtain
X4 = 3,
аз — 1,
x2 = -2,
xị = 1
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