5x² - y² = 3 2 x² + 2y² = 5 Point: -1, -√2

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Show all work to verify if the given point is a solution to the system of equations.

 

### System of Equations and Points

We have a system of two equations given by:

\[ 5x^2 - y^2 = 3 \]

\[ x^2 + 2y^2 = 5 \]

Additionally, we have a specific point mentioned:

\[ \text{Point:} \left( -1, -\sqrt{2} \right) \]

#### Explanation:

1. **Equation 1: \(5x^2 - y^2 = 3\)**
   - This equation represents a conic section known as a hyperbola when both \(x\) and \(y\) are real numbers.

2. **Equation 2: \(x^2 + 2y^2 = 5\)**
   - This equation represents an ellipse when both \(x\) and \(y\) are real numbers.

3. **Point: \(\left( -1, -\sqrt{2} \right)\)**
   - This is a specific point in the Cartesian coordinate system which can be tested for its position relative to the conic sections defined by the above equations.

#### Graphical Representation:
To understand how these equations and points relate to each other, we would typically plot them on the Cartesian plane:

- **Hyperbola:**
  - The hyperbola will have branches depending on the values of \(x\) and \(y\) that satisfy the first equation.

- **Ellipse:**
  - The ellipse will have its shape determined by the second equation, showing an oval-like figure on the graph.

### Analysis
Verifying if the given point \(\left( -1, -\sqrt{2} \right)\) lies on either or both of the curves involves substituting \(x = -1\) and \(y = -\sqrt{2}\) into each of the equations.

1. **Substitute into Equation 1:**
   \[5(-1)^2 - (-\sqrt{2})^2 = 5 - 2 = 3 \]
   - Satisfies the first equation.

2. **Substitute into Equation 2:**
   \[(-1)^2 + 2(-\sqrt{2})^2 = 1 + 4 = 5 \]
   - Satisfies the second equation.

Since the point \(\left( -1, -\sqrt{2} \right)\
Transcribed Image Text:### System of Equations and Points We have a system of two equations given by: \[ 5x^2 - y^2 = 3 \] \[ x^2 + 2y^2 = 5 \] Additionally, we have a specific point mentioned: \[ \text{Point:} \left( -1, -\sqrt{2} \right) \] #### Explanation: 1. **Equation 1: \(5x^2 - y^2 = 3\)** - This equation represents a conic section known as a hyperbola when both \(x\) and \(y\) are real numbers. 2. **Equation 2: \(x^2 + 2y^2 = 5\)** - This equation represents an ellipse when both \(x\) and \(y\) are real numbers. 3. **Point: \(\left( -1, -\sqrt{2} \right)\)** - This is a specific point in the Cartesian coordinate system which can be tested for its position relative to the conic sections defined by the above equations. #### Graphical Representation: To understand how these equations and points relate to each other, we would typically plot them on the Cartesian plane: - **Hyperbola:** - The hyperbola will have branches depending on the values of \(x\) and \(y\) that satisfy the first equation. - **Ellipse:** - The ellipse will have its shape determined by the second equation, showing an oval-like figure on the graph. ### Analysis Verifying if the given point \(\left( -1, -\sqrt{2} \right)\) lies on either or both of the curves involves substituting \(x = -1\) and \(y = -\sqrt{2}\) into each of the equations. 1. **Substitute into Equation 1:** \[5(-1)^2 - (-\sqrt{2})^2 = 5 - 2 = 3 \] - Satisfies the first equation. 2. **Substitute into Equation 2:** \[(-1)^2 + 2(-\sqrt{2})^2 = 1 + 4 = 5 \] - Satisfies the second equation. Since the point \(\left( -1, -\sqrt{2} \right)\
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