Consider the following system: 2х + 3у — 2х х — 2у + 32 - 2y + 4z 1 1 %3D 2x – 2 (a) Find the equations, in parametric form, of the intersecting line of the first two planes (i.e., 2x + 3y – 2z = 1 and – - 2y + 3z = -1). (b) Use part (a) to solve the system by finding the point of intersection of the line with the third plane.
Consider the following system: 2х + 3у — 2х х — 2у + 32 - 2y + 4z 1 1 %3D 2x – 2 (a) Find the equations, in parametric form, of the intersecting line of the first two planes (i.e., 2x + 3y – 2z = 1 and – - 2y + 3z = -1). (b) Use part (a) to solve the system by finding the point of intersection of the line with the third plane.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Consider the following system:
2х + Зу — 22
х — 2у + 32
2x – 2y + 4z
1
-1
-2
-
(a) Find the cquations, in paramctric form, of the intersccting line of the first two plancs
(i.е., 2л + 3у - 22
1 and x – 2y + 3z = –1).
(b) Use part (a) to solve the system by finding the point of intersection of the line with
the third plane.
Expert Solution

Step 1
The given equations are
2x + 3y - 2z = 1
x - 2y + 3z = -1
2x - 2y + 4z = -2
to find the parametric form of equation of first two intersecting line is..
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