2х1 + X2 — 4хз + 3x4 — 0 X2 + 3x3 – 2x4 = 0 2х1 + 3х2 + 2х3 -4x1 ° - X4 = 0 — Зх2 + 5х3 — 4x4 — 0 b.
2х1 + X2 — 4хз + 3x4 — 0 X2 + 3x3 – 2x4 = 0 2х1 + 3х2 + 2х3 -4x1 ° - X4 = 0 — Зх2 + 5х3 — 4x4 — 0 b.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
please solve 4 (b)
Transcribed Image Text:4. In each part solve the linear system by the elimination method
-2y + 3z = 1
3х + 6у — 3z %3D —9
бх + 6у + 3z %3D 5
а.
2x1 + x2
X2 + 3x3 – 2x4 = 0
2х1 + 3x2 + 2хз — Х4 — 0
-4x1 – 3x2 + 5x3 – 4x4 = 0
4xз + 3х4 — 0
|
b.
5. Determine the values of a for which the system has no
solutions, exactly one solution, or infinitely many solutions
x + 2y + z = 2
2х — 2у + 3z %3D1
х + 2у — (а? — 3)z %3Dа
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