Research is being carried out on cellulose as a source of chemicals for the production of fibers, coatings, and plastics. Cellulose consists of long chains of glucose molecules (C6H12O6), so for the purposes of modeling the reaction we can consider the conversion of glucose to formaldehyde (H2CO).Calculate the heat of reaction for the conversion of 1 mole of glucose into formaldehyde, given the following thermochemical data:H2CO (g) + O2 (g) → CO2 (g) +H2O (g) ΔH°comb = –572.9 kJ/mol6C (s) + 6H2 (g) + 3O2 (g) → C6H12O6 (s) ΔH°f = –1274.4 kJ/molC (s) + O2 (g) → CO2 (g) ΔH°f = –393.5 kJ/molH2 (g) + 1/2 O2 (g) → H2O (g) ΔH°f = –285.8 kJ/molWhat is the ΔH°rxn for the reaction below?C6H12O6 (s) → 6H2CO (g)

To get the final equation, First equation has to be reversed and multiplied by 6. Second equation…

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Research is being carried out on cellulose as a source of chemicals for the production of fibers, coatings, and plastics. Cellulose consists of long chains of glucose molecules (C₆H₁₂O₆), so for the purposes of modeling the reaction we can consider the conversion of glucose to formaldehyde (H₂CO).

Calculate the heat of reaction for the conversion of 1 mole of glucose into formaldehyde, given the following thermochemical data:

H₂CO (g) + O₂ (g) → CO₂ (g) +H₂O (g) ΔH°_comb = –572.9 kJ/mol

6C (s) + 6H₂ (g) + 3O₂ (g) → C₆H₁₂O₆ (s) ΔH°_f = –1274.4 kJ/mol

C (s) + O₂ (g) → CO₂ (g) ΔH°f = –393.5 kJ/mol

H₂ (g) + 1/2 O₂ (g) → H₂O (g) ΔH°_f = –285.8 kJ/mol

What is the ΔH°_rxn for the reaction below?

C₆H₁₂O₆ (s) → 6H₂CO (g)

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