Refer to this equation: 2NaMnO4(aq) + H2O2(aq) + 3H2SO4(aq) → 2MnSO4(aq) + Na2SO4(aq) + 3O2(g) + 4H2O(l). 30.0 g of NaMnO4 was reacted with excess H2O2 and H2SO4 . The O2 gas was collected 1.80 atm and at 35.00 oC . How many L of pure O2 gas should theoretically be present if yield is 100%? Molar mass NaMnO4 is 141.9 g. Hint: calculate the amount of moles O2 that will be made, and use PV = nRT to calculate L Hint: you must convert oC to K by adding 273
Refer to this equation: 2NaMnO4(aq) + H2O2(aq) + 3H2SO4(aq) → 2MnSO4(aq) + Na2SO4(aq) + 3O2(g) + 4H2O(l). 30.0 g of NaMnO4 was reacted with excess H2O2 and H2SO4 . The O2 gas was collected 1.80 atm and at 35.00 oC . How many L of pure O2 gas should theoretically be present if yield is 100%? Molar mass NaMnO4 is 141.9 g. Hint: calculate the amount of moles O2 that will be made, and use PV = nRT to calculate L Hint: you must convert oC to K by adding 273
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Refer to this equation:
2NaMnO4(aq) + H2O2(aq) + 3H2SO4(aq) → 2MnSO4(aq) + Na2SO4(aq) + 3O2(g) + 4H2O(l).
30.0 g of NaMnO4 was reacted with excess H2O2 and H2SO4 . The O2 gas was collected 1.80 atm and at 35.00 oC .
How many L of pure O2 gas should theoretically be present if yield is 100%? Molar mass NaMnO4 is 141.9 g.
Hint: calculate the amount of moles O2 that will be made, and use PV = nRT to calculate L
Hint: you must convert oC to K by adding 273
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