5. Toxic chromate can be precipitated from an aqueous solution by bubbling SO₂ through the solution. How many grams of SO2 are required to treat 3.0 x 108 L of 0.050 mM CrO4²-? 2 CrO4² (aq) + 3 SO2(g) + 4 H*(aq) → Cr₂(SO4)3(s) + 2 H₂O(1)

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**Problem 5:** Toxic chromate can be precipitated from an aqueous solution by bubbling SO₂ through the solution. Calculate the mass of SO₂ required to treat 3.0 × 10⁸ L of a 0.050 mM CrO₄²⁻ solution.

**Chemical Equation:**

\[ 
2 \text{CrO}_4^{2-} \, (aq) + 3 \text{SO}_2 \, (g) + 4 \text{H}^+ \, (aq) \rightarrow \text{Cr}_2(\text{SO}_4)_3 \, (s) + 2 \text{H}_2\text{O} \, (l) 
\]
Transcribed Image Text:**Problem 5:** Toxic chromate can be precipitated from an aqueous solution by bubbling SO₂ through the solution. Calculate the mass of SO₂ required to treat 3.0 × 10⁸ L of a 0.050 mM CrO₄²⁻ solution. **Chemical Equation:** \[ 2 \text{CrO}_4^{2-} \, (aq) + 3 \text{SO}_2 \, (g) + 4 \text{H}^+ \, (aq) \rightarrow \text{Cr}_2(\text{SO}_4)_3 \, (s) + 2 \text{H}_2\text{O} \, (l) \]
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