The amount of nickel(II) present in an aqueous solution can be determined by precipitating the nickel with the organic chemical reagent dimethylglyoxime [CH3 C(NOH)C(NOH)CH3, commonly abbreviated as "DMG"]. Ni²+ (aq) + 2DMG (aq) → Ni(DMG)2 (s) + 2H+ (aq) How many milliliters of 0.0567 M DMG solution are required to precipitate all the nickel(II) present in 10.9 mL of 0.293 M nickel(II) sulfate solution? mL

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Chapter4: Chemical Reactions
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Problem 4.141QP: Lead(II) nitrate reacts with cesium sulfate in an aqueous precipitation reaction. What are the...
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The amount of nickel(II) present in an aqueous solution can be determined by precipitating the nickel with the organic chemical
reagent dimethylglyoxime [CH3 C(NOH)C(NOH)CH3, commonly abbreviated as "DMG"].
Ni²+ (aq) + 2DMG(aq) → Ni(DMG)2 (s) + 2H+ (aq)
How many milliliters of 0.0567 M DMG solution are required to precipitate all the nickel(II) present in 10.9 mL of 0.293 M
nickel(II) sulfate solution?
mL
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Transcribed Image Text:The amount of nickel(II) present in an aqueous solution can be determined by precipitating the nickel with the organic chemical reagent dimethylglyoxime [CH3 C(NOH)C(NOH)CH3, commonly abbreviated as "DMG"]. Ni²+ (aq) + 2DMG(aq) → Ni(DMG)2 (s) + 2H+ (aq) How many milliliters of 0.0567 M DMG solution are required to precipitate all the nickel(II) present in 10.9 mL of 0.293 M nickel(II) sulfate solution? mL Submit Answer Try Another Version 10 item attempts remaining
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