The reaction of the mineral fluorapatite with sulfuric acid follows the equation: Ca10F2(PO4)6(s) + 7 H2SO4(aq) → 2 HF (↑) + 3 Ca(H2PO4)2(s)+ 7 CaSO4(s) If you started with 245 g of fluorapatite, how many grams of either solid could you produce? How many moles of gas would be released? Please show all the work step by step and with the explanation
The reaction of the mineral fluorapatite with sulfuric acid follows the equation: Ca10F2(PO4)6(s) + 7 H2SO4(aq) → 2 HF (↑) + 3 Ca(H2PO4)2(s)+ 7 CaSO4(s) If you started with 245 g of fluorapatite, how many grams of either solid could you produce? How many moles of gas would be released? Please show all the work step by step and with the explanation
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The reaction of the mineral fluorapatite with sulfuric acid
follows the equation:
Ca10F2(PO4)6(s) + 7 H2SO4(aq) → 2 HF (↑) + 3 Ca(H2PO4)2(s)+ 7 CaSO4(s)
If you started with 245 g of fluorapatite, how many grams of
either solid could you produce? How many moles of gas would
be released? Please show all the work step by step and with the explanation.
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