How many moles of ammonia would be required to react exactly with 0.470 moles of copper(II) oxide in the following chemical reaction? 2 NH3(g) + 3 CuO(s) → 3 Cu(s) + N2(g) + 3 H2O(g) mol
How many moles of ammonia would be required to react exactly with 0.470 moles of copper(II) oxide in the following chemical reaction? 2 NH3(g) + 3 CuO(s) → 3 Cu(s) + N2(g) + 3 H2O(g) mol
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question:**
How many moles of ammonia would be required to react exactly with 0.470 moles of copper(II) oxide in the following chemical reaction?
**Chemical Reaction:**
\[ 2 \text{NH}_3(g) + 3 \text{CuO}(s) \rightarrow 3 \text{Cu}(s) + \text{N}_2(g) + 3 \text{H}_2\text{O}(g) \]
**Answer:**
\[ \underline{\hspace{3cm}} \text{ mol} \]
**Explanation for Educational Purposes:**
In this balanced chemical equation, 2 moles of ammonia (\(\text{NH}_3\)) react with 3 moles of copper(II) oxide (\(\text{CuO}\)). To determine how many moles of ammonia are needed for 0.470 moles of copper(II) oxide, we set up a proportion based on the stoichiometry of the reaction:
The ratio of \(\text{NH}_3\) to \(\text{CuO}\) is 2:3. Therefore:
\[
\frac{2 \text{ moles NH}_3}{3 \text{ moles CuO}} = \frac{x \text{ moles NH}_3}{0.470 \text{ moles CuO}}
\]
Solving for \(x\), the required moles of ammonia can be calculated easily.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8a647020-6631-4fab-b41d-15f56d9331d0%2F504f3b68-e013-4107-b123-47d5f648ea03%2Fx2r9xks_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
How many moles of ammonia would be required to react exactly with 0.470 moles of copper(II) oxide in the following chemical reaction?
**Chemical Reaction:**
\[ 2 \text{NH}_3(g) + 3 \text{CuO}(s) \rightarrow 3 \text{Cu}(s) + \text{N}_2(g) + 3 \text{H}_2\text{O}(g) \]
**Answer:**
\[ \underline{\hspace{3cm}} \text{ mol} \]
**Explanation for Educational Purposes:**
In this balanced chemical equation, 2 moles of ammonia (\(\text{NH}_3\)) react with 3 moles of copper(II) oxide (\(\text{CuO}\)). To determine how many moles of ammonia are needed for 0.470 moles of copper(II) oxide, we set up a proportion based on the stoichiometry of the reaction:
The ratio of \(\text{NH}_3\) to \(\text{CuO}\) is 2:3. Therefore:
\[
\frac{2 \text{ moles NH}_3}{3 \text{ moles CuO}} = \frac{x \text{ moles NH}_3}{0.470 \text{ moles CuO}}
\]
Solving for \(x\), the required moles of ammonia can be calculated easily.
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