How many moles of ammonia would be required to react exactly with 0.470 moles of copper(II) oxide in the following chemical reaction? 2 NH3(g) + 3 CuO(s) → 3 Cu(s) + N2(g) + 3 H2O(g) mol

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Question:**

How many moles of ammonia would be required to react exactly with 0.470 moles of copper(II) oxide in the following chemical reaction?

**Chemical Reaction:**

\[ 2 \text{NH}_3(g) + 3 \text{CuO}(s) \rightarrow 3 \text{Cu}(s) + \text{N}_2(g) + 3 \text{H}_2\text{O}(g) \]

**Answer:**

\[ \underline{\hspace{3cm}} \text{ mol} \]

**Explanation for Educational Purposes:**

In this balanced chemical equation, 2 moles of ammonia (\(\text{NH}_3\)) react with 3 moles of copper(II) oxide (\(\text{CuO}\)). To determine how many moles of ammonia are needed for 0.470 moles of copper(II) oxide, we set up a proportion based on the stoichiometry of the reaction:

The ratio of \(\text{NH}_3\) to \(\text{CuO}\) is 2:3. Therefore:

\[
\frac{2 \text{ moles NH}_3}{3 \text{ moles CuO}} = \frac{x \text{ moles NH}_3}{0.470 \text{ moles CuO}}
\]

Solving for \(x\), the required moles of ammonia can be calculated easily.
Transcribed Image Text:**Question:** How many moles of ammonia would be required to react exactly with 0.470 moles of copper(II) oxide in the following chemical reaction? **Chemical Reaction:** \[ 2 \text{NH}_3(g) + 3 \text{CuO}(s) \rightarrow 3 \text{Cu}(s) + \text{N}_2(g) + 3 \text{H}_2\text{O}(g) \] **Answer:** \[ \underline{\hspace{3cm}} \text{ mol} \] **Explanation for Educational Purposes:** In this balanced chemical equation, 2 moles of ammonia (\(\text{NH}_3\)) react with 3 moles of copper(II) oxide (\(\text{CuO}\)). To determine how many moles of ammonia are needed for 0.470 moles of copper(II) oxide, we set up a proportion based on the stoichiometry of the reaction: The ratio of \(\text{NH}_3\) to \(\text{CuO}\) is 2:3. Therefore: \[ \frac{2 \text{ moles NH}_3}{3 \text{ moles CuO}} = \frac{x \text{ moles NH}_3}{0.470 \text{ moles CuO}} \] Solving for \(x\), the required moles of ammonia can be calculated easily.
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