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Refer to the following figure. Consider the quasi-static expansions of an ideal gas between the equilibrium states A and C. If 500 J of heat are added to the gas as it traverses the path ABC, how much heat is required for the transition along ADC? Assume that pi = 2.00 × 105 Pa, = 1.00 x 105 Pa, Vị = 2.20 × 10-3 m³ , and V2 = 4.00 x 10–3 m³. Again, the change in internal energy is independent of the path. P2 D V1 V2

Refer to the following figure. Consider the quasi-static expansions of an ideal gas between the equilibrium states A and C. If 500 J of heat are added to the gas as it traverses the path ABC, how much heat is required for the transition along ADC? Assume that pi = 2.00 × 105 Pa, = 1.00 x 105 Pa, Vị = 2.20 × 10-3 m³ , and V2 = 4.00 x 10–3 m³. Again, the change in internal energy is independent of the path. P2 D V1 V2

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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1. Refer to the following figure. Consider the quasi-static expansions of an ideal gas between the equilibrium states A and C. If 500 J of heat are added to the gas as it traverses the path ABC, how much heat is required for the transition along ADC? Assume that Pi = 2.00 x 105 Pa, P2 1.00 x 105 Pa, Vị = 2.20 × 10-3 m³ , and V2 4.00 × 10-3 m³. Again, the change in internal energy is independent of the path. A P1 P2 V V1 V2 FIG. 1: Problem 4.
Transcribed Image Text:1. Refer to the following figure. Consider the quasi-static expansions of an ideal gas between the equilibrium states A and C. If 500 J of heat are added to the gas as it traverses the path ABC, how much heat is required for the transition along ADC? Assume that Pi = 2.00 x 105 Pa, P2 1.00 x 105 Pa, Vị = 2.20 × 10-3 m³ , and V2 4.00 × 10-3 m³. Again, the change in internal energy is independent of the path. A P1 P2 V V1 V2 FIG. 1: Problem 4.
Expert Solution
Step 1

Given:

p1 = 2.0*105 Pap2=1.0*105 PaV1=2.20*10-3m3V2=4.0*10-3 m3

let path ABC = 1

and path ADC = 2

thus,

dQ1 = 500 JdU1=dU2  (since, change in internal energy is path independent)

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