You need to design a gas with a y (= Cp/Cv) value of 1.5. While no individual gas has this value, you could produce such a gas by mixing together a monatomic gas and a diatomic gas. What fraction or percentage of the molecules in the mixture needs to be monatomic? [Hint: for a monatomic gas Cv = (3/2)R and for a diamotic gas Cy = (5/2)R.]
You need to design a gas with a y (= Cp/Cv) value of 1.5. While no individual gas has this value, you could produce such a gas by mixing together a monatomic gas and a diatomic gas. What fraction or percentage of the molecules in the mixture needs to be monatomic? [Hint: for a monatomic gas Cv = (3/2)R and for a diamotic gas Cy = (5/2)R.]
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![You need to design a gas with a y (= Cp/Cv) value of 1.5. While no individual gas has this
value, you could produce such a gas by mixing together a monatomic gas and a diatomic gas.
What fraction or percentage of the molecules in the mixture needs to be monatomic? [Hint: for a
monatomic gas Cv = (3/2)R and for a diamotic gas Cy (5/2) R.]
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F739452bb-bec9-43d8-9372-35dc57efa9d5%2F74368edf-ae92-4b86-8f5f-612dc63a4b5d%2Fi99aadb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:You need to design a gas with a y (= Cp/Cv) value of 1.5. While no individual gas has this
value, you could produce such a gas by mixing together a monatomic gas and a diatomic gas.
What fraction or percentage of the molecules in the mixture needs to be monatomic? [Hint: for a
monatomic gas Cv = (3/2)R and for a diamotic gas Cy (5/2) R.]
=
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