Can you help with number 5 uploaded in the picture. *This is not and will not be graded For a point along the y-axis of a circular current-carrying loop21AB =4t (R? + y²)3/2where R is the radius of the loop and A = TR.For a point in the center:HolB2RFor a point a distance r away from an infinitely long straight current carrying wire%3DНо 214T rBIn a similar way to how we derived the results above, you can derive the B-field at a point a distancer away from the mid-point of a long straight current - carrying wire of length L:ILВ4t tVr2 + (L/2)²where L is the length of the wire and I is the current in the wire.The directions are given by the right-hand rule. 5. The figure below shows three parallel wires arranged in an equilateral triangle with sides oflength 10.0 cm. The wire at the apex carries a current of 3.0 A and points out of the pagewhile the two wires at the bottom has currents of 9.0 A and 19.0 A pointing into the page.Find the magnitude of the magnetic field at the point equidistant from the wires, using therules of vector addition to sum the contributions from each wire.3.0 A9.0 A 10.0 cm 19.0 A10.0 cm-10.0 cm-

Given: sides of equilateral triangle s = 10.0 cm current in each wire I1 = 3.0 AI2 = 9.0 AI3 = 19.0…

Answered: 3.0 A 9.0 A 10.0 cm-19.0 A 10.0cm -10.0…

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3.0 A 9.0 A 10.0 cm-19.0 A 10.0cm -10.0 cm

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter24: Magnetic Fields

Section: Chapter Questions

Problem 67A

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Question

Can you help with number 5 uploaded in the picture.

*This is not and will not be graded

For a point along the y-axis of a circular current-carrying loop
21A
B =
4t (R? + y²)3/2
where R is the radius of the loop and A = TR.
For a point in the center:
Hol
B
2R
For a point a distance r away from an infinitely long straight current carrying wire
%3D
Но 21
4T r
B
In a similar way to how we derived the results above, you can derive the B-field at a point a distance
r away from the mid-point of a long straight current - carrying wire of length L:
IL
В
4t tVr2 + (L/2)²
where L is the length of the wire and I is the current in the wire.
The directions are given by the right-hand rule.

5. The figure below shows three parallel wires arranged in an equilateral triangle with sides of
length 10.0 cm. The wire at the apex carries a current of 3.0 A and points out of the page
while the two wires at the bottom has currents of 9.0 A and 19.0 A pointing into the page.
Find the magnitude of the magnetic field at the point equidistant from the wires, using the
rules of vector addition to sum the contributions from each wire.
3.0 A
9.0 A 10.0 cm 19.0 A
10.0 cm
-10.0 cm-

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