An ideal diatomic gas has an initial pressure of 1.00×10°Pa , an initial volume of 2.00m', andan initial temperature of 300K. (This is point 1 on the pV-diagram.) The gas has an isochoricincrease in pressure to 2.00×10°P. . (This is point 2 on the pV-diagram.) The gas then has anisothermal expansion to a volume of 3.00m'. (This is point 3 on the pV-diagram.) The pressureis then reduced adiabatically back down to its original pressure of 1.00×10°P.. (This is point 4on the pV-diagram.) Finally, the gas has an isobaric decrease in volume to its original volume of2.00m. (The gas is back to point 1 on the pV-diagram.)а.Fill in the missing values on the following table.PointVolume,Pressure,Temperature,v (m²)p(10ʻPA)T(K)12.001.0030022.0033.0041.00b. Fill in the values for each of the processes in the following table. (These valuescorrespond to the First Law of Thermodynamics written as: AE, =W +Q.)ProcessChange in internalWork done to gas,Heat added to gas,energy, AE, (J)W (3)Q(1)'th1→ 22 → 33 → 44 →1Full Cycle

Iso choric process is the process where the system volume remain constant during the process. Iso…

Answered: An ideal diatomic gas has an initial…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A gas expands from I to F in the figure below. The energy added to the gas by heat is 302 J when the gas goes from I to Falong the diagonal path. Three paths are plotted on a PV diagram, which has a horizontal axis labeled V(liters), and a vertical axis labeled P (atm). The green path starts at point I (2,4), extends vertically down to point B(2,1), then extends horizontally to point F (4,1). The blue path starts at point I (2,4), and extends down and to the right to end at point F (4,1). The orange path starts at point I(2,4), extends horizontally to the right to point A (4,4), then extends vertically down to end at point F(4,1). (a) What is the change in internal energy of the gas?J(b) How much energy must be added to the gas by heat for the indirect path IAF to give the same change in internal energy?J
During an isothermal process, the number of mols of a gas is doubled while the pressure is held constant. By what factor did the gas volume change?
When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV to the power of 1.4 = C where C is a constant. Suppose that at a certain instant the volume is 480 cubic centimeters and the pressure is 75 kPa and is decreasing at a rate of 10 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant? Please Write legible
The PV diagram shows the compression of 40.9 moles of an ideal monoatomic gas from state A to state B. Calculate Q, the heat added to the gas in the process A to B. Data: PA= 1.90E+5 N/m2 VA= 1.83E+0 m3 PB= 1.01E+5 N/m2 VB= 8.90E-1 m3›44
Two evacuated bulbs are connected by a tube of negligible volume. The volume of one of the bulbs is twice that of the other. The larger volume bulb is placed in a 200K Isother constant-temperature bath and the other in a 300K bath, and then 1.00mol of an ideal me gas is injected into the system. Find the final number of moles of gas in each bulb.
A particular thermodynamic cycle acting on a monatomic ideal gas (y = 1.67) includes an isobaric expansion, an isochoric cooling, and then a isothermic contraction. The PV diagram is shown in the image below. P V The isobaric expansion occurs at a pressure of 1.8 × 105 Pa and changes the volume of the gas from 6.7 x 10-2 m³ to 13.08 × 102m³. What is the efficiency of the process?
An ideal monatomic gas undergoes changes in pressure and volume, as shown in the pV diagram below. The initial volume is 0.02 m3 and the final volume is 0.10 m3. The initial pressure is 1 atm and the final pressure is 2 atm. Recall that 1 atm = 101.3 kPa. (a) Calculate the magnitude, or absolute value, of the work done on the gas in this process. Answer = - 13429J (c) The initial temperature of the gas is 308 K. Calculate the temperature of the gas at the end of the process. Answer = 3080 k Just need answer with the following: (d) What is the change in thermal energy for the gas in this process? (e) Calculate the quantity of heat transfer added to (positive) or removed from (negative) the gas during this process.
two canisters A and B each contain 0.20 mol of a diatomic gas at 400k and a pressure of 405300 Pa. A expands isothermally and B adiabatically until pressure of each is 303975 Pa. [for a diatomic gas Cv = (2/5) R 1) Sketch both processes on a single PV diagram 2) What are the final temperature and final volume of each canister
A particular thermodynamic cycle acting on a monatomic ideal gas (y = 1.67) includes an isobaric expansion, an isochoric cooling, and then a isothermic contraction. The PV diagram is shown in the image below. P V The isobaric expansion occurs at a pressure of 2.265 × 105 Pa and changes the volume of the gas from 5.9 × 10 2 m³ to 10.98 × 10-2 m³. What is the efficiency of the process?
An ideal diatomic gas undergoes an adiabatic compression during which time its volume changes from VA = 1300 cm3 to VB = 390 cm3. If its initial temperature is TA = 74.0°C, what is the final temperature TB of the gas?
1.7 Ideal gas response functions Find the thermal expansion coefficient and the isothermal compressibility for an ideal gas and show that in this case Cp - Cy = - a² can be reduced to Cp – Cy = Nkg for the molar specific heats. TV Кт
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