) Recall that the simple random walk is just a Markov chain on the integers where we move from j to j+1 with probability, and from j to j-1 with probability: 2., Find P(Xn+1 =j+1| Xn = j) = 2 1 P(Xn+1 =j-1 | Xn = j) = 2/2 P(Xn+1 = m | Xn = j) = 0 ifm #j+1 or j - 1. (a) P(X+1 = 2 | X, = 0) (i.e. the probability of going from 0 to 2 in one-step) (b) P(X+1 = 2 | X,,= 1) (i.e. the probability of going from 1 to 2 in one-step) (c) P(Xn+2 = 2 | X₁ = 2) (i.e. the probability of going from 2 to 2 in two-steps)

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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2.
) Recall that the simple random walk is just a Markov chain on the integers where we move
from j to j+1 with probability, and from j to j-1 with probability: .
Find
1
P(Xn+1 =j+1| Xn = j) =
2
1
P(Xn+1 =j-1 | Xn = j) = ²/
P(Xn+1 = m | Xn = j) = 0 ifm #j+1 or j - 1.
(a) P(Xn+1 = 2 | X, = 0) (i.e. the probability of going from 0 to 2 in one-step)
(b) P(X+1 = 2 | X,,= 1) (i.e. the probability of going from 1 to 2 in one-step)
(c) P(Xn+2= 2 | X, = 2) (i.e. the probability of going from 2 to 2 in two-steps)
Transcribed Image Text:2. ) Recall that the simple random walk is just a Markov chain on the integers where we move from j to j+1 with probability, and from j to j-1 with probability: . Find 1 P(Xn+1 =j+1| Xn = j) = 2 1 P(Xn+1 =j-1 | Xn = j) = ²/ P(Xn+1 = m | Xn = j) = 0 ifm #j+1 or j - 1. (a) P(Xn+1 = 2 | X, = 0) (i.e. the probability of going from 0 to 2 in one-step) (b) P(X+1 = 2 | X,,= 1) (i.e. the probability of going from 1 to 2 in one-step) (c) P(Xn+2= 2 | X, = 2) (i.e. the probability of going from 2 to 2 in two-steps)
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