0 0 0 are steady-state vectors 0 3/5 0 2/5 for the Markov chain below. If the chain is equally likely to begin in each of the states, what is the probability of being in state 2 after many steps? Show that q₁ = P= 3/11 3/11 5/11 and 9₂5 = 1 2 3 1/3 1/4 1/4 1/3 1/4 1/3 1/2 1/4 1/2 4 0 0 0 5 1 0 0 2 0 3 The vector q, is a steady-state vector because ap pq₁ q/p-1 p-¹a₁ simplified fraction for each

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Q: [0.22 0.13 0.65] T = 0.10 Lo.00 0.82 0.181 0.70 0.20

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