Reaction rate0.350.300.250.200.15-0.100.050.00010002000Enzyme total is 5mM300040001.Substrate concentration1. The above graph is an enzyme reaction, what is the vMax, KM, and Kcat of thisenzymatic reaction? What does vMax, kM and Kcat mean, explain?2. What are the three forms of regulation that follow the Michaelis Menten kinetics? Whatare the mechanisms by which these inhibitors can regulate the enzyme?

MM graph is constructed by taking substrate and reaction velocity on X and Y axes respectively. The…

Answered: Reaction rate 0.35 0.30 0.25 0.20 0.15-…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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The KM values for the reaction of chymotrypsin with two different substrates are given in the table below. Considering this information, which substrate has the lower apparent affinity for the enzyme? Which substrate is likely to give a lower value for Vmax? Substrate N-acetylvaline ethyl ester N-acetyltyrosine ethyl ester KM (M) 8.8 X 10-² 6.6 X 10-4 N-acetylvaline ethyl ester has the lower apparent affinity for the enzyme; it will also likely to give a lower Vmax: N-acetyltyrosine ethyl ester has the lower apparent affinity for the enzyme; it will also likely to give the lower V₁ max. N-acetylvaline ethyl ester has the lower apparent affinity for the enzyme; N- acetyltyrosine ethyl ester is likely to give the lower Vmax: N-acetyltyrosine ethyl ester has the lower apparent affinity for the enzyme; N- acetylvaline will likely to give the lower Vmax. None of the above statements are correct.
The compound below which is labelled in two positions with 13c (as represented by the shaded spheres) was prepared and used to probe the mechanism of the aldolase enzyme employed in glycolysis. OH O Predict the pattern of 13c radiolabelling observed in the products: OH HO он 20,PO O LOPO,? но, OH 20,PO но. Hక్కి OH 20,PO Но, он 20;PO, HO. LOPO,2-
From the chart below, comment on the temperature dependence of this enzyme catalyzed reaction.
Consider the hypothetical biochemical pathway shown below. Assume that each letter (A, B, C, etc) represents a molecule and each number (1, 2, 3, etc) represents an enzyme. Draw arrows indicating all the probable feedback inhibition interactions that would be expected to regulate the activity of enzymes in this pathway.
5. For a Michaelis-Menten enzyme, k1 = 5.2 ⅹ 108 M-1 s-1, k-1 = 3.1 ⅹ 104 s-1, and k2 = 3.4 ⅹ 105 s-1. a) Write out the reaction, showing k1, k-1, and k2. Calculate Ks and Km. Does substrate binding approach equilibrium or the steady state? Justify your answer. b) What is kcat for this reaction? Justify your answer. c) Calculate Vmax for the enzyme. The total enzyme concentration is 25 pmol L-1, and each enzyme has two active sites. d) What substrate concentration would be required for the reaction in (c) to reach half of Vmax. Justify your answer mathematically. e) A second Michaelis-Menten enzyme has k1 = 4.2 ⅹ 107 M-1 s-1, k-1 = 6.1 ⅹ 104 s-1, and k2 = 5.3 ⅹ 102 s-1. Which enzyme is most efficient? 6. A pharmaceutical company is trying to develop a
The figure below shows the dependence of the enzyme's rate, v (in µM/min), as a function of substrate concentration, S (in mM). Also shown is the dependence of the rate in the presence of an inhibitor, present at a concentration of 0.2 mM. Based on this information, which of the following does this inhibitor most likely interact with? 1/v 1- 05 1/[S) O A. Michaelis complex O B. [E O C. free enzyme O D. free substrate O E. Both "A" and "B."
please help me understand this practice problem with as much details as possible. An enzyme reversibly binds a substrate. The rate constant (kcat) for catalytic conversion of enzyme- substrate complex into product and free enzyme is 1.0 s-1. The rate constant for dissociation of enzyme- substrate complex (k-1) is 9.0s^-1. 1) For each substrate binding event, what is the probability that substrate is converted into product rather than dissociated without conversion? 2) What is the probability that 20 consecutive binding events result in no product formation? 3) If you evaluated 1,000 different sets of 20 consecutive binding events, what would be the average number of product molecules formed (per 20 binding events)? 4) What is the probability that 20 consecutive binding events result in a number of product molecules at least equal to this average?
Chymotrypsin has the highest affinity for which of the following substrates: Table. The values of KM and kcat for some Enzymes and Substrates Enzyme Chymotrypsin Ки (М) 4.4 x 10-1 8.8 x 10-2 6.6 x 104 Kcat (S-1) 5.1 x 10-2 1.7 x 10-1 1.9 x 102 Substrate N-acetylglycine ethyl ester N-acetylvaline ethyl ester N-acetyltyrosine ethyl ester Catalase H2O2 2.5 x 10-2 1.0 x 107 Urease Urea 2.5 x 10-2 4.0 x 105 OA. N-acetylglycine ethyl ester OB. N-acetylvaline ethyl ester OC. N-acetyltyrosine ethyl ester D. Urea
4. a. Use the data in the graph above to estimate a KM value for the enzyme in the presence of these metabolites, and enter them into the table below. b. Classify these metabolites as either activators or inhibitors, and explain your rationale below.
The enzymatic activity of an enzyme with Kg = 2 mM that converts substrate S into product P is measured at an initial substrate concentration S, of 10 µM. After 5 min, the substrate concentration is halved. What is the rate constant k, the maximal velocity vmax and the concentration of product after 12 min?
1. The optimal conditions for salivary lysozyme (hydrolyzing glycoproteins ofbacterial wall) are 37 C- temperature and pH is 5.2. Explain the decrease in this enzyme activity if the temperature will rise up to 60 °C and pH will be changed to 8.0. To answer the question: a) draw the graph of the velocity dependency on temperature and pH; b) calculate the relative enzyme activity if 10 mg of lysozyme catalyzes the formation of 5 uM of the product per 2 minutes. 2 Consider the matic reaction schee: Asnaragine + H20 Aspartate+ NH3:
Lysozyme catalyzes a "bi-bi" reaction, which means there are (how many) reactants and (how many) products. List, in order, the reactants that bind and the products that are released during a lysozyme-catalyzed reaction cycle -- be succinct but be specific. 1. First reactant = 2. First product = 3. Second reactant = 4. Second product %3D

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