Radioactive radon occurs naturally as a product of uranium decay. The half life is 3 days. Suppose a flask originally contained 0.00000000000030 atoms of 222Rn. How many atoms will remain after 30 days?
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Concept:
To determine the number of atoms remaining after 30 days we will use the Half-life Formula that is,
Given:
Here in this is question Initial number of atoms is given to be 0.00000000000030 that is which is not possible thus there is a mistake in the question the number of atom should be
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- A piece of charcoal (totally carbon) from an ancient campsite has a mass of 262 grams. It is measured to have an activity of 29 Bq from 14C decay. Use this information to determine the age of the campfire. Your answer is required to be in years. Information: 14C half-life is 5730 years. 1 gram of living carbon has 6.52x1010 atoms of 14CE c) For a radio-nuclide, a number No of atoms at time t = 0 decays as N(t) = No e¯‹, where A is the decay constant. i) Derive the relationship between the half-life t₁ and the time constant □ = = 1/λ. ii) The radio-nuclide radium-226 has a half-life of 1600 years. Calculate the activity of one gram of radium in Becquerels. iii) Radium-226 decays to radon-222, known as the daughter product. The amount of a daughter product present will vary with time, Na(t). Sketch two graphs, with appropri- ate axes and labels, to show schematically how N(t) and Na(t) evolve if Na(0) = 0, for the two extreme cases where the daughter product is much more radioactive than the parent (\d >> \) and where the daughter product is much less radioactive than the parent (\a << λ). Given that the half-life of radon-226 is 3.8 days, indicate which graph is relevant and estimate the amount of radon in equilibrium with one mole of radium.In a living organism, a fixed fraction 1.30 × 10-12 of 12C is the radioactive isotope 14C, which has a half life of 5730 y. What is the activity of the 14C in 1.3 g of 12C found in living tissue in Bq?
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