Question IX Find za/2 for each of the following confidence levels used In estimating the populatlon mean. a. 90% b. 98% C. 88%
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Confidence Interval: In statistics, we can say a range of values of the population parameter will lies within it with some confidence is known as Confidence Interval.
Confidence Level: Confidence level is nothing but (1 - alpha)% which explains how much you are confident that the result will fall within the certain range.
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- Question 1 1. Which IAT data set are you working with? 2. 3. Use StatCrunch and your unique IAT sample to estimate the mean age for the population of IAT participants at the 90% confidence level. Copy the contents of your StatCrunch output window and paste them into your response. (No need to type anything here - just copy and paste the contents of your StatCrunch output window.) Are conditions met to estimate the mean age for the population of IAT participants? (Be sure to support your answer as demonstrated throughout Unit 8.) 4. State the confidence interval, and then interpret the confidence interval in context. 5. What is the margin of error (MOE)? 6. Which would be more accurate, the 90% confidence interval you found or an 85% confidence interval? Briefly explain. Which would be more precise? Briefly explain. One sample T confidence interval: μ: Mean of variable 90% confidence interval results: Variable Sample(IAT-Weight-Score) Sample Mean Std. Err. DF L. Limit U. Limit…The scores on a standardized mathematics test for 8th-grade children in New York State form a normal distribution with a mean of m= 70 and a SD=10. a. What proportion of the students in the state have scores less than X=75? b. If samples of n=4 are selected from the population, what proportion of the samples will have means less than M=75? c. If samples of n=25 are selected from the population, what proportion of the samples will have means less than M=75?RD.24.
- Question 3, 10.4.52QUESTION 23 Ali constructed a 98% confidence interval for the mean amount spent per day in a shopping mall based on 100 customers. The confidence interval was found to be (AED 1150, AED 2150). Select all correct answers. The mean amount spent per day by the 100 customers selected in the sample falls between AED 1150 and AED 2150. We are 98% confident that the mean amount spent per day by customers falls between AED 1150 and AED 2150. The mean amount spent per day by all customers falls between AED 1150 and AED 2150. 98% of all customers spent between AED 1150 and AED 2150 per day.Question 1. Greater than or Less than. Question 2. IS or IS NOT.
- The following is a sample of patient's calcium tests in mg/dL. 9.3 8.8 10.1 8.9 9.4 9.8 10.0 9.9 11.2 12.1 Find each of the following: The mean: The median: The third quartile: The standard deviation: The variance:Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with a mean of 3.2 pounds and a standard deviation of 0.8 pound. If a sample of 25 fish yields a mean of 3.1 pounds, what is the Z-score for this observation? Question 3 options: 1) 2.500 2) 0.625 3) -0.625 4) 1.250
- The average number of cavities that thirty-year-old Americans have had in their lifetimes is 4. Do twenty-year-olds have a different number of cavities? The data show the results of a survey of 11 twenty- vear-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 2, 5, 3, 2, 5, 3, 5, 2, 2, 2, 4 What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: ns Ho: ? vSelect an answer v re H: ? v Select an answer c. The test statistic 2 v = (please show your answer to 3 decimal places.) urse d. The p-value = e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that... (Please show your answer to 4 decimal places.) O The data suggest that the population mean number of cavities for twenty-year-olds is not significantly different from 4 at a = 0.05, so there is…Question 1 The mayor is interested in finding a 98% confidence interval for the mean number of pounds of trash per person per week that is generated in the city. The study included 220 residents whose mean number of pounds of trash generated per person per week was 36.6 pounds and the standard deviation was 7.7 pounds. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a ? v distribution. b. With 98% confidence the population mean number of pounds per person per week is between and pounds. c. If many groups of 220 randomly selected members are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of pounds of trash generated per person per week and about percent will not contain the true population mean number of pounds of trash generated per person per week.If other factors are held constant which of the following sets of data is most likely to produce a significant value for the repeated measures t statistics? n=15 and MD= 4 n=30 and MD =2 n=15 and MD= 2 n=30 and MD=4
