QUESTION 2A research study reported a 95% confidence interval for the mean time of hip surgeries based on a sample of 91 patients as (116 minutes, 138minutes). Which of the following statements is correct about the given interval?A. IncorrectB. CorrectThe mean time of hip surgeries of the 91 patients in the selectedsample falls between 116 and 138 minutes.✓The mean time of hip surgeries of any sample of 91 patients willfall between 116 and 138 minutes.95% of hip surgeries take between 116 and 138 minutes.We are 95% confident that the mean time of hip surgeries willbe between 116 and 138 minutes.

Solution - Given that, A research study reported a 95% confidence interval for the mean time of hip…

Answered: A research study reported a 95%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A research study reported a 95% confidence interval for the mean time of hip surgeries based on a sample of 91 patients as (116 minutes, 138 minutes). Which of the following statements is correct about the given interval? A. Correct B. Incorrect - We are 100% sure that the mean time of hip surgeries of the sampled 91 patients is between 116 and 138 minutes. -95% of the hip surgeries of the sampled 91 patients will fall between 116 and 138 minutes. We are 100% sure of hip surgeries take between 116 and 138 minutes. We are 95% sure that hip surgeries will take, on average, 116 to 138 minutes.
10 squirrels were found to have an average weight of 610 grams with a sample standard deviation of 7.75 . Find the 95 % confidence interval of the true mean weight (assume the t-student distribution). A.)(608.25, 614.16) B.)(561.02, 614.16) C.) (604.46,615.54) D.) (513.79, 612.77)
The number of hours of computer usage in a day of a random sample of 12 students was recorded as follows: 4.7, 3.9, 4.7, 4.8, 5.7, 6.1, 5.7, 5.3, 4.1, 3.1, 3.7, 4.0 What is the mean number of hours of computer usage?
Is there a difference between younger and older citizens in terms of interest in politics and current affairs? A brief quiz on recent headline stories was administered to four random samples of 12 respondents (N = 48) from each of the following age groups: High School (15-18 years of age), Young Adult (21-30), Middle-Aged (30-55), and Retired (65+). And the mean correct responses for each of these groups were as follows: the first group reported a mean of 3.7 correct answers, for the second group the mean was 4.4, for the third group it was 5.6, and for the fourth group it was 7.9 correct answers. Using the data from samples, it was determined that mean square between groups is equal to 41.4 and mean square within groups is 6.9. Is there a significant difference? Please use the five steps of hypothesis testing to conduct an analysis of variance test at the 0.05 significance level and summarize your conclusions in a sentence or two.
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Listed in the accompanying table are heights (in.) of mothers and their first daughters. The data pairs are from a journal kept by Francis Galton. Use the listed paired sample data, and assume that the samples are simple random samples and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test the claim that there is no difference in heights between mothers and their first daughters. Mother 64.0 66.0 63.0 62.0 66.5 66.0 65.0 60.0 67.0 63.0 Daughter 67.0 66.5 70.5 66.0 61.0 66.0 65.5 65.0 67.0 65.0 In this example, Hd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the daughter's height minus the mother's height. What are the null and alternative hypotheses for the hypothesis test? Ho: Ha = 0 in. H₁ Hd 0 in. (Type integers or decimals. Do not round.) Identify the test statistic. t= (Round to two decimal places as needed.)
The mean number of sick days an employee takes per year is believed to be about 10. Members of a personnel department do not believe this figure. They randomly survey 8 employees. The number of sick days they took for the past year are as follows: 10; 5; 13; 3; 11; 8; 6; 9. Let X = the number of sick days they took for the past year. Should the personnel team believe that the mean number is about 10? Conduct a hypothesis test at the 5% level.Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) What is the test statistic? (If using the z distribution round your answers to two decimal places, and if using the t distribution round your answers to three decimal places.) t = Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence…
A graduate student is interested in how viewing different types of scenes affects working memory. For his study, he selects a random sample of 36 adults. The subjects complete a series of working memory tests before and after walking in an urban setting. Before the walk, the mean score on the test of working memory was 9.1. After the walk, the mean score was 1.4 higher. The graduate student has no presupposed assumptions about how viewing different types of scenes affects working memory, so he formulates the null and alternative hypotheses as: H00 : μDD = 0 H11 : μDD ≠ 0 Assume that the data satisfy all of the required assumptions for a repeated-measures t test. The graduate student calculates the following statistics for his hypothesis test: Mean difference (MDD) 1.4 Estimated population standard deviation of the differences (s) 1.6 Estimated standard error of the mean differences (sMDMD) 0.2667 Degrees of freedom (df) 35 The t statistic 5.25 The critical values of t…
In a sample of 7 observations, the values are 17, 11, 12, 13, 14, 15. 16. Find the 95% confidence interval for the population mean. O A. (5.00, 9.00) O B. (4.00, 8.00) OC (12.00, 16.00) OD.(11.00, 15.00)
(in hours): 7, 6, 7, 8.5, 8, 9, 6.5 a. Find the mean, median, mode and standard deviation for their hours of sleep. b. Create a 99% confidence interval for the mean amount of hours they slept.
The following sample data are from a normal population: 10,9,12,14,13,11,6,5 c. With 95% confidence, what is the margin of error for the estimation of the population mean (to 1 decimal)? d. What is the 95% confidence interval for the population mean (to 1 decimal)? d.
When forming a confidence interval for matched-pair data the point estimate is the Select one: O A. standard deviation of the differences. OB. differences of the standard deviations. O C. mean of the differences. O D. difference of the means.

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