(c) At the 2 percent level of significance (a = .02) does the sample contradict the manufacturer's claim?Decision Rule: Reject HoThe samplethe manufacturer's claim(d) Find the p-value. (Round intermediate calculations to 2 decimal places. Round your answer to 4 decimal places.)p-value The mean potassium content of a popular sports drink is listed as 132 mg in a 32-oz bottle. Analysis of 24 bottles indicates a samplemean of 131.2 mg.(a) State the hypotheses for a two-tailed test of the claimed potassium content..a. Ho: μ= 132 mg vs. H₁:b. He: ≤132 mg vs. H₁:c. He:≥132 mg vs. H₁:OaObOc(b) Assuming a known standard deviation of 2.1 mg, calculate the z test statistic to test the manufacturer's claim. (Round your answerto 2 decimal places. A negative value should be indicated by a minus sign.)Test statistic132 mg>132 mg<132 mg(c) At the 2 percent level of significance (a = .02) does the sample contradict the manufacturer's claim?Decision Rule: Reject Ho

It is tested at that whether the mean potassium content differ form the stated value of 132mg.Sample size: Sample mean: Population standard deviation: The two tailed hypothesis is the set of hypthesis in which the alternative hypothesis contains not equals to sign.Among the given options,option(a) is the correct set of hypotheses as it only contains not equals to sign in the alternativ hypothesis.Therefore, the hypotheses for testing the claim will be:Rest of the two options are not correct set of hypotheses as they do not meet the condition of two tailed test.As the value of population standard deviation is known, we use z-test for testing the claim.The z-statistic is obtained as:The value of test statistic is .The two tailed p-value is obtained as:The p-value is obtained as .Note: The is obtained using the MS-excel formula "=NORMSDIST( )" and the required probability is obtained as:Decision Rule: If the p-value is less than the level of significance,we will reject the null hypothesis.Otherwise we fail to reject the null hypothesis.As in the given as the p-value is greater than the level of significance(0.02), we fail to reject the null hypothesis and hence, there is insufficient evidence to reject the manufacturer's claim that the mean potassium content is 132mg.,The option a is correct set of hypotheses which are:The test statistic is obtained as .At 2% level of significance, we fail to reject the manufacturer's claim that the mean potassium content is 132mg.The p-value is obtained as .