**Question 8**A simple random sample of 5 observations from a normal distribution was taken, and the following values were obtained: {12, 15, 15, 17, 21}. A 90% confidence interval for the mean is:- A. (13.553, 18.447)- B. (14.378, 17.622)- C. (13.567, 18.432)- D. (13.553, 18.447)- E. (11.883, 20.117)**Question 9**A population has a standard deviation of 8. What is the minimum sample size needed to estimate a mean to within 2 units with 66.8% confidence?- A. 13- B. 15

Question 8) Solution: n= 5 Sample size To find sample mean and sample standard deviation x…

Answered: A simple random sample of 5…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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From a sample of 18 tellers operating in different branches of a bank, it turned out that during a day an average of 60 people are served, with a variance of 81. Construct an interval for the population mean, with 95 % confidence.Select one:a. μ= [56,524 ;63,476]b. μ= [55,524 ;64,476]c. μ= [55,324 ;64,376]d. μ= [55,842 ;64,158]e. μ= [56,542 ;64,467]
53.305) B. (24.591, 35.563) C. (26.591, 37.563) D. (28.591, 39.563) 34. A simple random sample of size n = 36 is taken from a normally distributed original population. The sample standard deviation iss = 7. Find the 99% confidence interval for the population variance o2. A. (27.453, 98.756) B. (28.453, 99.756) C. (29.453, 100.756) D. (30.453, 101.756)
4. In the ordered data: 20, a, 25, 30, 40, b, 49. If the first quartile=23.5 and IQR=19, then the values of a and b are: a=21.5, b=45.5 a=21, b=48 a=22, b=45 a=22.5 , b=45.5 5. Let X-Bin (12, 0.2), then * P (X 2 1) = O 1- 0.212 O 0.812 O1- 0.812 O 0.212
Suppose that the mean weight of 9 randomly selected students in a school is 62.6 kg with a standard deviation of 2.7 kg. Assuming that the weights of all students is normally distributed, which of the following is the 95% confidence limits for the population mean weight? Select correct / closest choice. Select one: a. (60.564, 64.636) b. (60.926, 64.274) C. (60.525, 64.675) d. (59.581, 65.62) e. (60.836, 64.364)
Construct a 95% confidence interval for the population standard deviation σ of a random sample of 15 men who have a mean weight of 165.2 pounds with a standard deviation of 10.7 pounds. Assume the population is normally distributed. A. (8.226,15.618) B. (2.395,5.159) C. (61.368,284.75) D. (7.834,16.875)
The following sample observations were randomly selected x: 4, 5, 3, 6, 10 y: 4, 6, 5, 7, 7 round to three decimal places a. determine the 95% confidence interval for the mean predicted when x = 7 (_____, _____) b. determine the 95% prediction interval for an individual predicted when x = 7 (_____, _____).
A study of 4 bolts of carpet showed that their average length was 76.2 yards and the sample standard deviation was 5.6 yards. Which of the following is the 80% confidence interval for the mean length per bolt of carpet? O A. 75.8 to 76.6 O B. 72.62 to 79.78 O C. 71.61 to 80.79 D. 75.40 to 77.00
A sample of values taken from a normally distributed population are 6.8, 7.2, 5.4, 8.8 and 10.2. If the standard deviation of the population is 2.1 determine the range of the sample values within which the mean of the population has a 95% probability of lying.
Assume the heights of faculty at Champlain College are normally distributed with a mean of 68.1 inchesand a standard deviation of 1.3 inches. Which of the following values best approximates the probabilityof randomly selecting a Champlain College faculty membershorterthan 67.5 inches tall?A. 0.0668B. 0.3228C. 0.5001D. 0.6772E. 0.9332
Suppose that the average number of Facebook friends users have is normally distributed with a mean of 136 and a standard deviation of about 45. Assume forty-two individuals are randomly chosen. Answer the following questions. Round all answers to 4 decimal places where possible. Find the third quartile for the average number of Facebook friends
The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.6 days and a standard deviation of 2.3 days. 1.) What is the probability of spending more than two days in recovery? A.)0.8709 B.) 0.0495 C.) 0.9412 D.) 0.0588 2.) The 80th percentile for recovery times is? A.) 7.54 B.) 4.24 C.) 7.01 D.) 6.81
Twenty-two car salespeople were sampled to see how many cars they sold in a month; the following data was obtained: 26, 20, 22, 18, 21, 14, 24, 28, 17, 23, 28, 29, 18, 17, 24, 26, 19, 27, 26, 22, 23, 25 Construct a 95% confidence interval for the mean number of cars sold per month by the population of car salespeople. S = t = Margine of Error: E = We are 95% confident that, on average, car salespeople sell between cars and cars per month.

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A simple random sample of 5 observations from a normal distribution was taken, and the following values were obtained: {12, 15, 15, 17, 21}. A 90% confidence interval for the mean is O A. (13.553, 18.447) O B. (14.378, 17.622) O C. (13.567, 18.432) O D. (13.553, 18.447) O E. (11.883, 20.117)