**Question 8**A simple random sample of 5 observations from a normal distribution was taken, and the following values were obtained: {12, 15, 15, 17, 21}. A 90% confidence interval for the mean is:- A. (13.553, 18.447)- B. (14.378, 17.622)- C. (13.567, 18.432)- D. (13.553, 18.447)- E. (11.883, 20.117)**Question 9**A population has a standard deviation of 8. What is the minimum sample size needed to estimate a mean to within 2 units with 66.8% confidence?- A. 13- B. 15

Question 8) Solution: n= 5 Sample size To find sample mean and sample standard deviation x…

Answered: A simple random sample of 5…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a random sample of eight people, the mean driving distance to work was 24 2 miles and the standard deviation was 7.5 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 99% confidence interval for the population mean p. Interpret the results. Identify the margin of error. (Round to one decimal place as needed.)
The sample mean for the fill weights of 100 boxes is 12.050. The population variance of the fill weights is known to be (0.100)2. Find a 95% confidence interval for the population mean u fill weight of the boxes. O a. [12.301, 12.702] O b. [11.830, 11.070] O c. [11.030, 11.070] O d. [12.030, 12.070]
1. The strength of a fiber is normally distributed with a known population standard deviation of 12 kg. An engineer sampled random pieces of fiber, and got the following data: 43, 54, 74.2, 47, 61.6, 80, 38, 40, 32 Find the 96% confidence interval for the mean strength of the fiber.
A simple random sample of 1000 people age 18 or over is taken in a large town. It turns out that 223 people in the sample are newspaper readers. Calculate a 90%-confidence interval for the percentage of people (age 18 and over) in that town who read newspapers. Choose the closest answer. a. (19.7%, 24.9%) b. (21.5%, 23.0%) c. (21.0%, 23.5%) d. (20.1%, 24.5%)
10 squirrels were found to have an average weight of 610 grams with a sample standard deviation of 7.75 . Find the 95 % confidence interval of the true mean weight (assume the t-student distribution). A.)(608.25, 614.16) B.)(561.02, 614.16) C.) (604.46,615.54) D.) (513.79, 612.77)
Samples of two different models of cars were selected, and the actual speed for each car was determined when the speedometer registered 50 mph. The resulting 95% confidence intervals for true mean actual speed were (51.2, 52.6) and (49.2, 50.4). Assuming that the two sample standard deviations are equal, which confidence interval is based on the larger sample size? O (51.2, 52.6) O (49.2, 50.4) Explain your reasoning. O As the sample size increases, the width of the interval increases. O As the sample size increases, the width of the interval decreases.
A simple random sample of 5 observations from a normal distribution was taken, and the following values were obtained: {15, 19, 19, 20, 22}. A 95% confidence interval for the mean is O A. (16.569, 21.431) O B. (15.835, 22.165) O C.(16.069, 21.931) O D. (17.124, 20.876) O E. (16.765, 21.235)
53.305) B. (24.591, 35.563) C. (26.591, 37.563) D. (28.591, 39.563) 34. A simple random sample of size n = 36 is taken from a normally distributed original population. The sample standard deviation iss = 7. Find the 99% confidence interval for the population variance o2. A. (27.453, 98.756) B. (28.453, 99.756) C. (29.453, 100.756) D. (30.453, 101.756)
79. What is the 90% confidence interval for the difference in population proportions, p1 – p2 , given the following sample data: [-0.0772 , 0.1172] [-0.0499 . 0.0899] [-0.0710 , 0.1110] [-0.0603 , 0.1003]
The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the two rear wheels of eight cars and runs the cars until the tires wear out. The data (in kilometers) follow. Find a 99% confidence interval on the difference in the mean life. Car Brand 1 Brand 2 1 36,925 34,318 2 45,300 42,280 3 36,256 35.548 4 32,100 31,950 5 37,210 38,015 6 48,360 47,800 7 38.200 37,810 8 33,500 33,215 Round your answer to 2 decimal places. Do not use commas.
Suppose that you have a four-sided die that is equally weighted (i.e. equal chance of any of the four sides landing face up). The four values on the die are [12.5968, 2, -2 and -12.5968] . What is the standard deviation using the conceptual definition? That is, what is the average distance from the data points to the mean? A. 5.34 B. 4.09 C. 2.58 D. 7.29
Twenty-five wooden beams were ordered for a construction project. The sample mean and the sample standard deviation were measured: x = 230 cm, s = 6 cm. Calculated confidence interval for the mean is [226.64; 233.36]. Which confidence level was chosen? Assume distribution to be normal. O 90% O 99% O 95% O 99.9%

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A simple random sample of 5 observations from a normal distribution was taken, and the following values were obtained: {12, 15, 15, 17, 21}. A 90% confidence interval for the mean is O A. (13.553, 18.447) O B. (14.378, 17.622) O C. (13.567, 18.432) O D. (13.553, 18.447) O E. (11.883, 20.117)