Question 9 Consider the following data collected in a study concerning animal preference and choice of car. What is the probability a randomly chosen individual in this study has a Subaru Outback? Pet/Vehicle preference Subaru Outback Fiat 500 Total Cat 200 300 Dog 400 100 Total 60% 20% 40% 50%
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- Are birthdays "evenly distributed" throughout the year, or are they more common during some parts of the year than others? Owners of a children's toy store chain asked this question. Some data collected by the chain are summarized in the table below. The data were obtained from a random sample of 180 people. The birthdate of each person was recorded, and each of these dates was placed into one of four categories: winter (December 21-March 20), spring (March 21-June 20), summer (June 21-September 20), and fall (September 21-December 20). The numbers in the first row of the table are the frequencies observed in the sample for these season categories. The numbers in the second row are the expected frequencies under the assumption that birthdays are equally likely during each season of the year. The bottom row of numbers gives the following value for each of the season categories. (Each expert I have asked has gotten the critical value wrong so I added a picture of the correct formula to…A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…A random sample of 10 compact cars, 10 mid-size cars, and 10 luxury cars were selected. The time (in seconds) each of the randomly selected cars required to accelerate from 0 to 60 mph was looked up on the Autos.com website. The results are presented below. Car Type Time (in seconds) Required to Accelerate from 0 to 60 mph Compact 9.3 8.1 10.2 8.8 9.0 9.3 7.7 9.2 9.4 8.6 Mid-Size 6.9 5.7 8.3 7.7 8.6 5.9 6.1 8.8 6.1 7.2 Luxury 5.7 6.3 5.4 4.7 6.2 7.0 5.9 5.3 6.3 5.0 Conduct a hypothesis test using ! = 0.05 to determine whether the mean time required to accelerate from 0 to 60 mph is the same for compact, mid-size, and luxury cars. (No accounting or excel, I need help solving it.)
- Microsoft Word -... 56% of students entering four-year colleges receive a degree within six years. Is this percent larger than for students who play intramural sports? 170 of the 278 students who played intramural sports received a degree within six years. What can be concluded at the level of significance of a = 0.10? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Select an answer ✓ Ho: ? H₁: ? Select an answer (please enter a decimal) (Please enter a decimal) (please show your answer to 3 decimal places.) c. The test statistic ? ✓ = d. The p-value = e. The p-value is ? a f. Based on this, we should Select an answer the null hypothesis. g. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) O The data suggest the populaton proportion is significantly larger than 56% at a = 0.10, so there is sufficient evidence to conclude that the population proportion of students who played intramural sports who…Need urgent help pleaseInternational experience around the world is important in our culture of globalization. According to NAFSA, 54.5% of all American students traveling abroad went to Europe in the 2014-2015 academic year. To determine if there is shift in the proportion of students traveling to Europe, suppose a random sample of 300 students who had studied abroad was taken for the 2015-2016 school year. One-hundred sixty of the students traveled to Europe. a. Conduct a test to determine if the proportion of students traveling to Europe has changed. Be sure to provide a complete write-up. b. Based on the hypothesis test, would you expect 0.545 to be in confidence interval for the proportion? Explain without constructing the interval.
- The type of household for the U.S. population and for a random sample of 411 households from a community in Montana are shown below. Observed Number of Households in the Community Percent of U.S. Type of Household Households Married with children 26% 110 Married, no children Single parent One person Other (e.g., roommates, siblings) 29% 101 32 25% 98 11% 70 Use a 5% level of significance to test the claim that the distribution of U.S. households fits the Dove Creek distribution. (a) What is the level of significance? State the nul and alternate hypotheses. O Ho: The distributions are different. H: The distributions are the same. O Hg: The distributions are the same. H: The distributions are different. O Hg: The distributions are the same. H: The distributions are the same. O Hg: The distributions are different. H: The distributions are different. (b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to two decimal places. Round the test…Is there an association between hair color and body type? The table below shows the results of a researcher's observations of randomly selected people. Frequencies of Hair Colors for Various Body Types Blonde Brunette Red Head 71 80 96 108 55 115 46 91 Short and Slender Short and Pudgy Tall and Slender Tall and Heavy What can be concluded at the o= 0.01 significance level? 53 74 69 63
