QUESTION 5 Suppose an electron (q = – e= - 1.6 × 10¬19 C,m=9.1 × 10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the inal speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K = -U Since K = mv² and using the formula for potential energy above, we arrive at an equation for speed: v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s v=

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