QUESTION 5 Suppose an electron (q = – e= - 1.6 × 10¬19 C,m=9.1 × 10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the inal speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K = -U Since K = mv² and using the formula for potential energy above, we arrive at an equation for speed: v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s v=
QUESTION 5 Suppose an electron (q = – e= - 1.6 × 10¬19 C,m=9.1 × 10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the inal speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K = -U Since K = mv² and using the formula for potential energy above, we arrive at an equation for speed: v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s v=
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 23P
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Please fill in the blanks. Suppose an electron (q equals negative e equals negative 1.6 cross times 10 to the power of negative 19 end exponent space text C end text space,m equals 9.1 cross times 10 to the power of negative 31 end exponent space text kg end text) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures.
![QUESTION 5
Suppose an electron (q = - e= -1.6 × 10¬19 c ,m=9.1 × 10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the
final speed of the electron. Express numerical answer in two significant figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:
U =
Assuming all potential energy U is converted to kinetic energy K,
K+U = 0
K= -U
1
=5mv and using the formula for potential energy above, we arrive at an equation for speed:
Since K
v = (
1/2
Plugging in values, the value of the electron's speed is:
x 107 m/s
V=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F23ec2101-1ee4-459c-b4bc-a29537c5cc7b%2F324a87a2-1083-48da-b753-1b5002d29a42%2Ffwweu7_processed.png&w=3840&q=75)
Transcribed Image Text:QUESTION 5
Suppose an electron (q = - e= -1.6 × 10¬19 c ,m=9.1 × 10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the
final speed of the electron. Express numerical answer in two significant figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:
U =
Assuming all potential energy U is converted to kinetic energy K,
K+U = 0
K= -U
1
=5mv and using the formula for potential energy above, we arrive at an equation for speed:
Since K
v = (
1/2
Plugging in values, the value of the electron's speed is:
x 107 m/s
V=
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