Path of trajectoryAVAn electron is fired at a speed vj = 4.7 x 106 m/s and at anangle 0; = 37.1° between two parallel conducting plates asshown in the figure. If s = 2 mm and the voltage differencebetween the plates is AV = 99.6 V, determine how close, w,the electron will get to the bottom plate. Put your answerin meters and include at 6 decimal places in your answer.Do not include units. The x-axis of the coordinatesystem is in the middle of the parallel plate capacitor.

Magnitude of the electric field between the plates

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