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![Question 4: [6 marks]
Let a be a real number such that 0 < a < 1. Use the contradiction method to prove that a <√a.
(of course, we assume that 0 < √a).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7825aad8-d50f-4c82-80e8-3c170dc836f7%2F425998ff-71f7-423f-a69d-77740a051b3b%2Fvaea8s8_processed.jpeg&w=3840&q=75)
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- Prove the mathematical statements 7. If a and x are real numbers with 0 < xQuestion 2. Express each statement in plain English. Then decide if the statement is true or false (including a brief explanation). Both x and y represent real numbers. (1) \xy(x² + y² ≤ 4) (2) \x³y(x² + y² ≤ 4) (3) ³xVy(x² + y² ≤ 4)Find the number in {x E R:-2Recommended textbooks for youAdvanced Engineering MathematicsAdvanced MathISBN:9780470458365Author:Erwin KreyszigPublisher:Wiley, John & Sons, Incorporated
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