Why is the one I chose wrong? Which is the correct one and why? Therefore there must exist a natural number m such that nx < m< ny, and by dividing through by n we have x< m 1= nz <1= ny-nx < 1Therefore there must exist a natural number m such that ny - nx We assume that x0. Therefore there exists a natural number n such that n>1 Since z is fixed we can simply evaluate 1 and take the next largest natural number. Which of the following completes the proof?We have thatn>1= nz >1a ny-nx> 1.Therefore there must exist a natural number m such that nx < m < ny, and by dividing through by n we have xm » nz <1→ ny-nx < 1Therefore there must exist a natural numberm such that ny - nx nTherefore x <

Suppose that x and y are 2 distinct real numbers. We have to prove that, there exists a rational…

We assume that x0. Therefore there exists a natural number n such that n> Since z is fixed we can simply evaluate 1 and take the next largest natural number. Which of the following completes the proof?

We assume that x0. Therefore there exists a natural number n such that n> Since z is fixed we can simply evaluate 1 and take the next largest natural number. Which of the following completes the proof?

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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