Question 3 (a) Briefly explain THREE (3) disadvantages of Single Sideband (SSB) over Double Sideband Suppressed Carrier (DSBSC). (b) An AM DSBSC signal with a load resistance 50 2 has the following equation: VaMt) = 8 sin 21.53 x 10°t sin 11.88 x 10°t (V) Calculate the upper and lower sideband frequencies. ii. Determine the bandwidth.

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Question 3
(a)
Briefly explain THREE (3) disadvantages of Single Sideband (SSB) over Double
Sideband Suppressed Carrier (DSBSC).
(b)
An AM DSBSC signal with a load resistance 50 2 has the following equation:
VaMt) = 8 sin 21.53 x 10°t sin 11.88 x 10°t (V)
i.
Calculate the upper and lower sideband frequencies.
ii.
Determine the bandwidth.
iii.
Calculate the total power.
iv.
Sketch and label the resultant frequency spectrum.
(c)
An AM DSBFC signal has a carrier frequency of 300 kHz with peak amplitude is
17 V. The modulating frequency is 15 kHz with peak amplitude of 6 V.
i.
Determine the peak amplitude of the modulated sidebands.
ii.
Calculate the maximum and minimum amplitude of the envelope.
iii.
Sketch and label the resultant frequency spectrum.
iv.
Sketch and label the modulated signal in time domain.
Transcribed Image Text:Question 3 (a) Briefly explain THREE (3) disadvantages of Single Sideband (SSB) over Double Sideband Suppressed Carrier (DSBSC). (b) An AM DSBSC signal with a load resistance 50 2 has the following equation: VaMt) = 8 sin 21.53 x 10°t sin 11.88 x 10°t (V) i. Calculate the upper and lower sideband frequencies. ii. Determine the bandwidth. iii. Calculate the total power. iv. Sketch and label the resultant frequency spectrum. (c) An AM DSBFC signal has a carrier frequency of 300 kHz with peak amplitude is 17 V. The modulating frequency is 15 kHz with peak amplitude of 6 V. i. Determine the peak amplitude of the modulated sidebands. ii. Calculate the maximum and minimum amplitude of the envelope. iii. Sketch and label the resultant frequency spectrum. iv. Sketch and label the modulated signal in time domain.
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