Question 15 The results of the particle-size analysis of a soil are as follows: • Percent passing the No. 10 sieve = 80 • Percent passing the No. 40 sieve = 40 • Percent passing the No. 200 sieve = 20 The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 30 and 5, respectively. Compute the group index. 2 B 1

Question 15 The results of the particle-size analysis of a soil are as follows: • Percent passing the No. 10 sieve = 80 • Percent passing the No. 40 sieve = 40 • Percent passing the No. 200 sieve = 20 The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 30 and 5, respectively. Compute the group index. 2 B 1

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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43.) The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 100 6 2.380 98 10 2.000 91 20 0.840 85 40 0.420 84 60 0.250 79 100 0.149 61 200 0.074 55 LL 60 PL 40 ML None of the above. CL CH MH
2. The following data were recorded during particle size analysis tests in the laboratory. Plot the grading curve and determine the grading characteristics. Using the information, classify the soil according to BSCS. Soil 1 Fine-Mesh dry sieve analysis data: Sieve Size 425 (mm or um) Mass 1.18 600 300 212 150 63 retained 1.9 3.2 8.1 10.4 22.7 126.1 (g) Total sample = 212.0 g
A liquid limit test on a clay was performed with the following results. The natural water content of the clay is 38% and plastic limit is 21%. Number of Blows 6 12 20 28 32 Water content (%) 52.5 47.1 42.3 38.6 37.5 What is the liquid limit of this clay? (Use Interpolation) Group of answer choices 39.85% 39.99% 36.74% 38.63% Please answer this asap for upvote. Thanks
Question 3: For an inorganic soil the following grain - size analysis is given. U.S sieve Percent analysis 4 passing 100 10 90 20 64 40 38 80 18 200 13 For this soil, LL=23 and Pl=19, classify the soil by using a. AASHTO b. USCS c. Give group name and group symbols
Problem 4: The following are the results of a sieve analysis. a. Determine the percent finer than each sieve and plot a grain-size distribution curve. b. Determine D10, D30, D60, for the soil. c. Calculate the uniformity coefficient Cu. d. Calculate the coefficient of gradation Cc. U.S. Sieve N 4 10 20 40 60 100 200 Pan U.S. Sieve N Mass of Soil Retained (g) Problem 5: Repeat problem 4 with the following data. 4 6 10 20 40 60 100 200 Pan 0 18.5 53.2 90.5 81.8 92.2 58.5 26.5 Mass of Soil Retained (g) 0 0 0 9.1 249.4 179.8 22.7 15.5 23.5
Using the unified classification system, what is the classification of soils that have the following results: 1-The percentage of those passing through sieve No. 4 =70% 2-The percentage of passing through sieve No. 200 = 38% 3-The liquidity limit LL = 42% 4-The plasticity limit = 26%
2.8 2.7 The following are the results of a sieve and hydrometer analysis. Sieve number/ grain size Analysis Sieve Hydrometer Analysis Sieve 40 80 170 200 0.04 mm 0.02 mm 0.01 mm 0.005 mm 0.0015 mm Hydrometer Sieve number/ grain size Percent finer than a. Draw the grain-size distribution curve. b. Determine the percentages of gravel, sand, silt, and clay according to the MIT system. c. Repeat Part b according to the USDA system. d. Repeat Part b according to the AASHTO system. Repeat Problem 2.7 with the following data: 20 30 40 60 80 200 0.05 mm 0.03 mm 0.015 mm 0.006 mm 0.004 mm 0.0015 mm 100 96 85 80 59 39 26 15 8 Cengage Learning 2014 Percent finer than 100 96 90 76 65 34 27 19 11 7 6 5 Ⓒ Cengage Learning 2014
Question 11 The results of the particle-size analysis of a soil are as follows: Percent passing the No. 10 sieve = 80 • Percent passing the No. 40 sieve = 40 Percent passing the No. 200 sieve = 20 %3D The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 30 and 5, respectively. Classify the soil by the AASHTO system. A A-2-4 B А-2-6 C) A-3 D A-2-5
05: The Figure below represents the data that was obtained from a liquid-limit test on a soil. 50 percent of its particles is passing sieve #200. Two determinations for the plastic limit gave water contents of 20.3 % and 20.8 %. Determine 1- Liquid Limit (LL). 2- Plasticity index. 3- Liquidity index if the water content is 27.4% 4- Void ratio at the liquid limit, if G, 2.7 5- Classify the soil based on AASHTO system. 30 10 20 40 60 80 100 Penetration, d (mm) Moisture content, w ()
QA:If the specific gravity of a soil 2.69 and dry unit weight 1.915 gm/cm2, the sample of this soil is dried from its state at plastic limit, the volume change is 25% of its own volume at plastic limit, Similarly, when the same sample is dried from its state of liquid limit, the volume change is 45% of its own volume at liquid limit. determine the plasticity index if the value of liquid limit = 35%. (Soil mechanic)
QA:If the specific gravity of a soil 2.69 and dry unit weight 1.915 gm/cm2, the sample of this soil is dried from its state at plastic limit, the volume change is 25% of its own volume at plastic limit, Similarly, when the same sample is dried from its state of liquid limit, the volume change is 45% of its own volume at liquid limit. determine the plasticity index if the value of liquid limit = 35%.
A sample of soil was tested in the laboratory, and the test results were listed as follows. Classify the soil by both the AASHTO and the USCS. - LL = 29%, PL = 19% Sieve Size 1 in 3/4 in 3/8 in #4 #10 #40 #200 Percent Passing 100 90 82 70 65 54 25