PROBLEM NO. 3 For an inorganic soil, the following grain size analysis is given: U.S. Sieve No. Diameter % Passing (mm) 4 4.75 100 10 2 90 20 0.85 64 40 0.425 38 80 0.180 18 200 0.075 4 Plasticity for the minus No. 40 fraction LL = 23 % PI = 19 % a. Compute the value of the Cu. b. Classify the soil using AASHTO system. c. Classify the soil using USCS.

PROBLEM NO. 3 For an inorganic soil, the following grain size analysis is given: U.S. Sieve No. Diameter % Passing (mm) 4 4.75 100 10 2 90 20 0.85 64 40 0.425 38 80 0.180 18 200 0.075 4 Plasticity for the minus No. 40 fraction LL = 23 % PI = 19 % a. Compute the value of the Cu. b. Classify the soil using AASHTO system. c. Classify the soil using USCS.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 96% No.200 = 52% Liquid Limit= 29 Plastic Limit = 11
Problem A: For questions 1 to 7. In the given results of the sieve analysis of a soil. Calculate the following; U.S. Opening Mass Sieve (mm) Retained, grams 4 4.75 10 2.00 21.6 20 0.850 49.50 40 0.425 102.60 60 0.250 89.10 100 0.150 95.60 200 0.075 60.4 Pan 31.2 Sum 1) For the problem above the most probable value for D10=. a) 0.15 mm 2) For D30 =_ a) 0.17 mm 3) For Dso = ? a) 0.27 mm 4) The Uniformity coefficient will be ? a) 4.56 5) The Coefficient of Gradation is? a) 0.90 6) The particle size distribution curve is what type? a) Gap-graded 7) Using the AASHTO system what is the percentage of sand? a) 6.90 b) 0.25 mm c) 0.67 mm d) 0.09 mm b) 0.27 mm c) 0.185 mm d) 0.03 mm b) 0.41mm c) 1.05 mm d) 0.21 mm b) 4.78 c) 3.98 d) 4.21 b) 0.93 c) 0.96 d) 1.15 b) Poorly Graded c) Well-graded b) 4.88 c) 72.90 d) 88.30
Situation 3. Following are the results of a sieve analysis. Determine: a. Cu b. Cc c. So Sieve No. 4 6 10 20 40 60 100 200 Pan Diameter (mm) 4.760 2.380 2.000 0.840 0.420 0.250 0.149 0.074 Soil Sample Mass Retained (g) 100 180 86 160 105 134 110 65 45
Someone can help me with this one. Please
Q5) A: Laboratory test results on the soil (L.L=35% and P.L-21%) is given in the following Table below. Classify the soil by using the unified classification system (10 mark) (showing all steps). Sieve Size(mm) Weight retained (gm) 4.75 2 0.425 0.25 0.075 Pan 135 70 60 30 142.5 462.5 B: A fine-grained soil has a liquid limit of 200% and a plastic limit of 45%, The natural water content of the soil in the field is 60% and the clay content is 63%, Calculate the plasticity index, the liquidity index and the activity. (10 mark)
Given below is the result of a sieve analysis done on a soil sample.Sieve No. Diameter Percent Passing %4 4.750 9510 2.000 8220 0.850 7340 0.425 5360 0.250 23100 0.150 14200 0.075 7Pan --- 0Determine the value of the coefficient of uniformity
Classify the soil by IS classification Given:- Liquid limit=22% Plasticity limit=19% Percentage passing through 4.75mm IS sieve=98.5% Percentage passing through 75 micron IS sieve=35% D60=0.22 D30=0.19 D10=0.16
Question 11 The results of the particle-size analysis of a soil are as follows: Percent passing the No. 10 sieve = 80 • Percent passing the No. 40 sieve = 40 Percent passing the No. 200 sieve = 20 %3D The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 30 and 5, respectively. Classify the soil by the AASHTO system. A A-2-4 B А-2-6 C) A-3 D A-2-5
1. A dry sand is placed in a container having a volume of 0.0092 cubic centimeter. The dry unit weightof the sample is 0.015 gram. Water is carefully added to the container so as not to disturbed thecondition of the sand. When the container is filled, the combined weight of soil plus water is 0.0182gram.a. Determine the specific gravity of soil particle.b. Determine the dry unit weight of soil.2. If the soil sample has a water content of 11% and a unit weight of 19.67 kN/m3 , determine thepercentage of air in voids and the degree of saturation if the specific gravity of soil solid is 2.75.3. If the soil sample has a specific gravity of 2.71 and a porosity of 0.345, determine the saturated unitweight and the bouyant unit weight.4. A soil sample having a liquidity index of 0.85, a plasticity index of 16.50 and a plastic limit of 11.45.The soil sample has a specicfic gravity of 2.68 and a void ratio of 0.77.a. Compute the degree of saturation.b. Compute the air void ratio.
Question 5 The results of the particle-size analysis of a soil are as follows: Percent passing the No. 10 sieve = 100 %3D Percent passing the No. 40 sieve = 80 • Percent passing the No. 200 sieve = 38 The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 40 and 15, respectively. Compute the group index. A) 1.75 1.0 2.5 2.0
The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 88 6 2.380 69 10 2.000 62 20 0.840 51 40 0.420 39 60 0.250 31 100 0.149 18 200 0.074 14 LL 60 PL 20 Determine its classification using USCS. SC SM ML None of the above. CL